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Python: Dividing values of nested list with values with values of dictionary


Python: Dividing values of nested list with values with values of dictionary

By : user2172131
Date : October 24 2020, 08:10 PM
it fixes the issue You can use a nested list comprehension, using key, *rest to unpack the elements of mylist and using dict.get to get the divisor or 1 as default:
code :
>>> [[key] + [x/mydict.get(key, 1) for x in rest] for key, *rest in mylist]
[['A', 2.0, 1.0, 2.5],
 ['C', 1.0, 3.0, 1.6666666666666667],
 ['D', 2.0, 5.0, 6.0]]


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get values from nested Dictionary using LINQ. Values of Dictionary are list of lists

get values from nested Dictionary using LINQ. Values of Dictionary are list of lists


By : Webster557
Date : March 29 2020, 07:55 AM
Hope that helps How to get values from nested Dictionary using LINQ. Keys in the Dictionary are integer. Values of Dictionary are list of lists. Seconday level list is a list of array holding integer value. in advance.
code :
Dictionary<int, List<List<int[]>>> dictionary = ...
var values = dictionary.Values.SelectMany(x => x.SelectMany(y => y.SelectMany(z => z));
Dividing values of dictionaries by values of another dictionary python

Dividing values of dictionaries by values of another dictionary python


By : Raghunath A
Date : March 29 2020, 07:55 AM
I wish did fix the issue. I have a dictionary, dict1, in the following format:
code :
def divide(dividends, divisors):
    ret = dict()
    for key, dividend in dividends.items():
        ret[key] = dividend/divisors.get(key, 1)
    return ret
Efficiently Iterating over dictionary list values by skipping missing values Python 3

Efficiently Iterating over dictionary list values by skipping missing values Python 3


By : user3544753
Date : March 29 2020, 07:55 AM
I hope this helps . I have a pandas dataframe , There is nothing wrong with simple continue.
code :
for key, value in newtagset.items():    # I found dict.items cleaner
    if not value[1]:
        continue
    df.loc...
Python nested dictionary and list concatnate dictionary keys with list values

Python nested dictionary and list concatnate dictionary keys with list values


By : hiko
Date : March 29 2020, 07:55 AM
hop of those help? I have a nested dict as follows:
code :
lst = {"A": ["1", "2", "3"], "B": ["2"], "C": ["1", "2"]}
result = ["{}.{}".format(key, val)
          for key, vals in lst.items()
          for val in vals]
print(result)
How can I analyze list values in a python dictionary, add extra dictionary values showing the different keys and the lis

How can I analyze list values in a python dictionary, add extra dictionary values showing the different keys and the lis


By : mattnthat
Date : March 29 2020, 07:55 AM
I hope this helps . So I hacked together a quick method for generating the dictionary you requested. For brevity, I used the np.intersect1d method to quickly count shared items between dict-value lists.
code :
import numpy as np

new_data = {} #new dict
for key in data_dict.keys():
    new_data[key] = () #set empty tuple
    x = [] #set empty list x
    y = [] #set empty list y
    for k, v in data_dict.items():
        if key == k: #don't count similarity on same key
            pass
        else:
            shared = np.intersect1d(data_dict[key],v) #all shared items
            if shared:
                for item in shared:
                    x.append(item) #add shared item to list x
                    y.append((k, len(shared))) # add k and number of shared items to list y
                new_data[key] = (list(set(x)),y) #update new dict
            else:
                pass #pass if no shared items found...
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