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cppwinrt A subclass of Panel (or other class),What constructors are needed?


cppwinrt A subclass of Panel (or other class),What constructors are needed?

By : Patrick Lynch
Date : October 24 2020, 08:10 PM
Does that help If you author a runtime class in C++/WinRT, you'll get several classes with the same name in different namespaces. Let's suppose that there's a namespace named NS1, in which there's a runtime class called WrapPanel, you'll get winrt::NS1::WrapPanel, winrt::NS1::implementation::WrapPanel and winrt::NS1::factory_implementation::WrapPanel. The first one is the "projection" of the runtime class, which we usually use; the second one is the "implementation", which implements the runtime class; the third one is the "factory", which is used by module.g.cpp.
If you convert a base class to a derived one, you should use the "projection". It seems that you have used the "implementation".
code :


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Duplicating base-class constructors to subclass?

Duplicating base-class constructors to subclass?


By : user1482241
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , You could add templated constructors for all possible parameters to your wrapper class:
code :
template<class Base>
class wrapper : public Base {
public:
  wrapper() : Base() {}

  template<typename T1>
  wrapper(T1 a1) : Base(a1) {}

  template<typename T1, typename T2>
  wrapper(T1 a1, T2 a2) : Base(a1, a2) {}

  // ...
};
class A {
public:
  A(int a) {};
};

int main() {
   wrapper<A> aw(1);
   return 0;
}
In Scala, how can I subclass a Java class with multiple constructors?

In Scala, how can I subclass a Java class with multiple constructors?


By : user2155030
Date : March 29 2020, 07:55 AM
With these it helps It's easy to forget that a trait may extend a class. If you use a trait, you can postpone the decision of which constructor to call, like this:
code :
trait Extended extends Base {
  ...
}

object Extended {
  def apply(arg1: Int) = new Base(arg1) with Extended
  def apply(arg2: String) = new Base(arg2) with Extended
  def apply(arg3: Double) = new Base(arg3) with Extended
}
Subclass constructors - Why must the default constructor exist for subclass constructors?

Subclass constructors - Why must the default constructor exist for subclass constructors?


By : Артем Павловский
Date : March 29 2020, 07:55 AM
To fix the issue you can do The important point is to understand that the first line of any constructor is to call the super constructor. The compiler makes your code shorter by inserting super() under the covers, if you do not invoke a super constructor yourself.
Also if you do not have any constructors an empty default constructor - here A() or B() - would automatically be inserted.
code :
public class B extends A<Integer> {
    public B (Integer i) {
        super(i);
    }
}
Does a subclass inherit constructors from it super class?

Does a subclass inherit constructors from it super class?


By : Aron Berg
Date : March 29 2020, 07:55 AM
I hope this helps you . A constructor from a subclass can call constructors from the superclass, but they're not inherited as such.
To be clear, that means if you have something like:
Why exactly do subclass constructors have to explicitly call super class constructors?

Why exactly do subclass constructors have to explicitly call super class constructors?


By : ubongo
Date : March 29 2020, 07:55 AM
Does that help They don't.
If you don't explicitly call a superconstructor, it's equivalent to calling the parameterless superconstructor.
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