Logical error in while statement when used with or operator

Logical error in while statement when used with or operator

By : user2172194
Date : October 24 2020, 08:10 PM
To fix this issue You'll probably need to re-ask the user if they don't give a valid input. Maybe something like this:
code :
name = input("Title: ").lower()
author = input("Author: ").lower()
valid = False
while not valid:
    has_read = input("Mark as Read (y/n): ").lower()
    if had_read in ['n', 'y']:
        valid = True
        if has_read == 'y':
            read = True
            read = False
        add_book(name, author, read)   

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Which logical operator do I want to use in this mysql statement?

Which logical operator do I want to use in this mysql statement?

By : Paul BB
Date : March 29 2020, 07:55 AM
it fixes the issue Your second statement is not going to return any results. A record cannot have option=ans and option=quest at the same time.
Logical Operator && in if statement

Logical Operator && in if statement

By : Francesco Caputo
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further If you put the test !(array[i][1] == 0 && array[i][2] == 'foo') in the loop control expression, then when that fails, the loop stops. It doesn't skip that iteration and continue to the next one any more than it would if i < array.length were false. It just stops.
If you want it to continue to the next iteration, you need to put the test in the loop body and use continue.
how many logical operator can we use in a statement in python?

how many logical operator can we use in a statement in python?

By : Wikytzone
Date : March 29 2020, 07:55 AM
around this issue , better to use in this way:
code :
while True:
    vari1=input("please enter your choice.")
    if vari1.lower() not in ['o','p']:
        print("please enter a appropriate choice") 
        # do your stuff 
>>> 1 in [1,2,3,4,5]
>>> 1 not in [1,2,3,4,5]
>>> 1 in [2,3,4,5]
>>> 1 not in [2,3,4,5]
PHP if statement && logical operator error

PHP if statement && logical operator error

By : Scott Griepentrog
Date : March 29 2020, 07:55 AM
wish of those help Please try this:
According to me, the array value is creating issue, so take this array value in another variable, just like this:
code :
$cat_val = $sCategory['sub_category_name'];
if (($cat_val == $subCat) && ($action == "edit")) {
    //Do stuff here
Logical operator in if statement

Logical operator in if statement

By : Stef H.
Date : October 02 2020, 11:00 PM
may help you . This: if(i == 20 || 30) is equivalent to if((i == 20) || 30) and 30 is always true.
If you really want to do what I think you want to do, you should have written:
code :
if(i == 20 || i == 30)
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