Python requests: having a space in header for posting

Python requests: having a space in header for posting

By : Dennis Wamelink
Date : October 24 2020, 08:10 AM
wish of those help I found a way to make this work: the problem I was having was due to the use of the urlencode function used in requests. In the requests documentation, it is shown how to go around this default behavior using PreparedRequests: http://docs.python-requests.org/en/master/user/advanced/#prepared-requests
Essentially, instead of using the requests.post() wrapper, make the function calls explicitly. This way, you will be able to control exactly what is sent. In my case, the solution was to do:
code :
import requests
data = {                                                                                                  
    'query': 'GetProcess',                                                                                                                                                                                     
    'getFrom': '2018-12-06 10:10:10.000'
s = requests.Session()
req = requests.Request('POST', 'http://'+ipAddress+'/monitor', data=data)
prepped = s.prepare_request(req)
prepped.body = prepped.body.replace("+", " ")
response = s.send(prepped)

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Posting to CloudApp API (AWS) with Python Requests

Posting to CloudApp API (AWS) with Python Requests

By : Aurie
Date : March 29 2020, 07:55 AM
it helps some times After several days, I finally figured out the (simple) problem. The CloudApp API requires a "GET" request to the "Location" header in Amazon's response.
Pycloudapp was working correctly because it properly authenticated the GET response with return json.load(self.upload_auth_opener.open(request)).
code :
#!/usr/bin/env python

import requests
from collections import OrderedDict
import keyring
import os

last_pic = '/path/to/image.jpg'

USER = 'myemail@email.com'

# replace with PASS = 'your_password' if you don't use keyring
PASS = keyring.backends.OS_X.Keyring.get_password(KEYCHAIN_SERVICE_NAME, USER)

AUTH_URL = 'http://my.cl.ly'
API_URL = 'http://my.cl.ly/items/new'

s = requests.Session()
s.auth = requests.auth.HTTPDigestAuth(USER, PASS)
s.headers.update({'Accept': 'application/json'})

upload_request = s.get(API_URL)
param_list = []
for key, value in upload_request.json()['params'].items():
    param_list.append((key.encode('utf8'), value.encode('utf8')))
data = OrderedDict(sorted(param_list))

filename = (os.path.basename(last_pic)).encode('utf8')
data['key'] = data['key'].replace(r'${filename}', filename)
files = {'file': (filename, open(last_pic,'rb').read()) }

stuff = requests.post(upload_request.json()['url'], data=data, files=files, allow_redirects=False)

Posting XML using python requests

Posting XML using python requests

By : Nick Awen
Date : March 29 2020, 07:55 AM
Does that help I am not going to rewrite it all but using str.format, kwargsa and triple quoted a string will make the code a lot less cluttered:
code :
def addVcsRoot(**kwargs):
    headers = {'Content-type': 'application/xml'}

    data = """<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
        <vcs-root id="{vcsRootId}"  name="{vcsRootName}"
        "vcsName="jetbrains.git" href="/app/rest/vcs-roots/id:"{vcsRootId}"\>""".format(**kwargs)
addVcsRoot(vcsRootId=1234, ......)
def addVcsRoot(vcsRootId, vcsRootName, projectId, projectName, buildName, repoId, teamAdminUser, teamAdminPass)
    headers = {'Content-type': 'application/xml'}

    data = """<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
    <vcs-root id="{vcsRootId}"  name="{vcsRootName}"
    "vcsName="jetbrains.git" href="/app/rest/vcs-roots/id:"{vcsRootId}"\>"""\
    .format(vcsRootI=vcsRootId, vcsRootName=vcsRootName.....)
Posting form data with requests and python

Posting form data with requests and python

By : James
Date : March 29 2020, 07:55 AM
To fix the issue you can do You have few little mistakes in your code:
Check form's action parameter. Then url = "https://www.yellowpages.com/search" Second parameter is geo_location_terms not geo_locations_terms. You should pass query parameters in requests.get as params not as request data (data).
code :
import requests

search_terms = "Bars"
location = "New Orleans, LA"
url = "https://www.yellowpages.com/search"
q = {'search_terms': search_terms, 'geo_location_terms': location}
page = requests.get(url, params=q)
Missing Host header in HTTP requests from the requests Python library

Missing Host header in HTTP requests from the requests Python library

By : user3153233
Date : March 29 2020, 07:55 AM
This might help you The HOST header is not being added to the request by requests by default. If it is not explicitly added then the decision is delegated to the underlying http module.
See this section of http/client.py:
code :
    if self._http_vsn == 11:
        # Issue some standard headers for better HTTP/1.1 compliance

        if not skip_host:
            # this header is issued *only* for HTTP/1.1
            # connections. more specifically, this means it is
            # only issued when the client uses the new
            # HTTPConnection() class. backwards-compat clients
            # will be using HTTP/1.0 and those clients may be
            # issuing this header themselves. we should NOT issue
            # it twice; some web servers (such as Apache) barf
            # when they see two Host: headers

            # If we need a non-standard port,include it in the
            # header.  If the request is going through a proxy,
            # but the host of the actual URL, not the host of the
            # proxy.

            netloc = ''
            if url.startswith('http'):
                nil, netloc, nil, nil, nil = urlsplit(url)

            if netloc:
                    netloc_enc = netloc.encode("ascii")
                except UnicodeEncodeError:
                    netloc_enc = netloc.encode("idna")
                self.putheader('Host', netloc_enc)
                if self._tunnel_host:
                    host = self._tunnel_host
                    port = self._tunnel_port
                    host = self.host
                    port = self.port

                    host_enc = host.encode("ascii")
                except UnicodeEncodeError:
                    host_enc = host.encode("idna")

                # As per RFC 273, IPv6 address should be wrapped with []
                # when used as Host header

                if host.find(':') >= 0:
                    host_enc = b'[' + host_enc + b']'

                if port == self.default_port:
                    self.putheader('Host', host_enc)
                    host_enc = host_enc.decode("ascii")
                    self.putheader('Host', "%s:%s" % (host_enc, port)) 
import requests

response = requests.get("http://httpbin.org/get")
print('Response from httpbin/get')
Response from httpbin/get
{'args': {}, 'headers': {'Accept': '*/*', 'Accept-Encoding': 'gzip, deflate', 
 'Host': 'httpbin.org', 'User-Agent': 'python-requests/2.20.0'},
 'origin': 'XXXXXX', 'url': 'https://httpbin.org/get'}

{'User-Agent': 'python-requests/2.20.0', 'Accept-Encoding': 'gzip, deflate', 
 'Accept': '*/*', 'Connection': 'keep-alive'}
Posting image using requests on python

Posting image using requests on python

By : Mario
Date : March 29 2020, 07:55 AM
I hope this helps . You are encoding the whole image into the request parameters, effectively extending the URL by the length of the image.
If you already encoded the image data, use the data parameter:
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