building dynamic XSLT in XQuery - using HTML passed into parameter

building dynamic XSLT in XQuery - using HTML passed into parameter

By : Diego Áquila
Date : October 24 2020, 08:10 AM
To fix this issue If you know you have an element with the right name and namespace (e.g. either span with no namespace for HTML 4 or HTML5 or span with the XHTML namespace for XHTML) and just want to copy it through to the output you don't need apply-templates at all, you can simply use directly.
But if you use apply-templates then obviously you need to ensure there is a template doing the right job (i.e. copying) you need, so either, as you have found, set up a template for span in the wanted mode that copies or set up a generic template like the identity transformation for that mode (or all modes with xsl:template mode="#all") that performs the copy.
code :

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XSLT and XQuery on invalid html input, pieces of URI look like entities

XSLT and XQuery on invalid html input, pieces of URI look like entities

By : Scott
Date : March 29 2020, 07:55 AM
will be helpful for those in need Make sure you have a correct xhtml DOCTYPE. According to the xhtml1-strict.dtd that I'm looking at, the href attribute is declared CDATA, not PCDATA, which means literal & is perfectly ok and should not be parsed as an entity.
Why would I choose XSLT or XQuery over the other for html document generation?

Why would I choose XSLT or XQuery over the other for html document generation?

By : Ivan Jestrovic
Date : March 29 2020, 07:55 AM
this will help XSLT is designed to take one xml document and transform it into something else, e.g. csv, html or a different xml format, e.g. xhtml.
XQuery is designed to extract information from one or more xml documents, and combine the result into a new xml document.
XSLT not getting parameter passed from javascript

XSLT not getting parameter passed from javascript

By : user3446868
Date : March 29 2020, 07:55 AM
this will help setParameter() will set a global variable(parameter).
You need to move the param-element out of the template-element to make it a child of the stylesheet-element, otherwise it will override the global parameter.
code :
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="section"/>
<xsl:template  match="/">   
        section=<xsl:value-of select="$section"/>
Using a parameter passed into xslt stylesheet

Using a parameter passed into xslt stylesheet

By : Jibber Jabber
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further You are using xsl:param inside a xsl:template element, it means that the param is for the template. The parameter you are passing from the .net code is a transformer parameter and related xsl:param must be placed at the top level of the stylesheet, into the xsl:stylesheet element.
calling XQuery from XSLT, building XSLT dynamically in XQuery?

calling XQuery from XSLT, building XSLT dynamically in XQuery?

By : Gabe
Date : March 29 2020, 07:55 AM
Hope that helps As XSLT is XML and with XQuery you can construct XML you can of course construct XSLT on the fly and inject data you gathered elsewhere in XQuery, the following is a silly example obviously but it constructs some data in XQuery, creates an XSLT stylesheet on the fly injecting some of that data directly inline as a parameter value and then runs the XSLT:
code :
declare namespace xsl = "http://www.w3.org/1999/XSL/Transform";

let $elements := (1 to 3)!<root><data>{.}</data></root>,
    $stylesheet := 
      <xsl:stylesheet version="2.0">
        <xsl:param name="data-elements" as="element()*">{$elements!data}</xsl:param>
        <xsl:template match="@* | node()">
             <xsl:apply-templates select="@* | node()"/>
        <xsl:template match="foo[. = $data-elements]"/>
    $input := <root><list><foo>a</foo><foo>2</foo><foo>10</foo><foo>1</foo></list></root>
return transform:transform($input, $stylesheet, ())
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