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How to get the details of a person whose earning in a day is greater than or equal to their earning in the previous day


How to get the details of a person whose earning in a day is greater than or equal to their earning in the previous day

By : bosscheng
Date : October 24 2020, 08:10 AM
it should still fix some issue You can use Lag() here as well which is supported in both MySQL and SQL server. LAG() is a "Window Function" that creates chunks of records (PARTITION BY) for distinct values (here we use person). It also orders the records in those chunks/windows/partitions and allows you to run logic against them. LAG() picks the previous record's value inside that ordered partition. In this case, it gets the previous day's earning for each record's person.
code :
SELECT person, 
    earning as current_day_earning, 
    LAG(earning) OVER (PARTITION BY person ORDER BY day) as previous_day_earning 
FROM info;
SELECT *
FROM
    (
        SELECT person, 
            earning as current_day_earning, 
            LAG(earning) OVER (PARTITION BY person ORDER BY day) as previous_day_earning 
        FROM info;
     ) curr_and_prev
 WHERE current_day_earning > previous_day_earning


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Earning through Ads Admob

Earning through Ads Admob


By : Tom Klein
Date : March 29 2020, 07:55 AM
This might help you I recently started developing a game for android and put the banner ads in it. I have not yet published the game as I wanted everything to be configured first. ,
how Admob earning is calculated
Does Interstitial ads help us to get more earning than Banner ads?

Does Interstitial ads help us to get more earning than Banner ads?


By : user3527084
Date : March 29 2020, 07:55 AM
wish helps you The answer is.... it depends.... I know, I know, it's kind of cop out answer, but it does. For instance, you might make more on interstitials per view but if your user engagement drops severely or leads to a higher uninstall rate because of them, then you actually net a negative outcome.
It also depends on how sophisticated your app is and how large your user population is. If you could partner with ad partners that serve ads/offers specifically your target demographic you could make a good CPM while annoying your users less.
Adsense Invalid Earning

Adsense Invalid Earning


By : MrDerdiet
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , No there is not. However 90% is users clicking on ads that did not want too, or users ending up with a bad experience. Go over your ads one by one and make sure that users do not accidentally click on your ads. This way you should not have any invalid earnings.
How do I get employee details if they are earning more than their paylevel?

How do I get employee details if they are earning more than their paylevel?


By : xharkie
Date : March 29 2020, 07:55 AM
this will help Given the information you provided (and without actual table schemas unfortunately) the following would act as a guide.
The basic premis is that the actual pay an employee earns needs to compared to the expected pay by means of matching the pay levels up in each table:
code :
SELECT emp.ID, emp.PayLevel, emp.ActualPay, pl.PayLevel, pl.Pay_Level_Name, pl.ExpectedPay
FROM Employees emp
INNER JOIN Paylevels pl ON pl.PayLevel = emp.PayLevel
WHERE  emp.ActualPay > pl.ExpectedPay
SELECT ac.accountant_id, ac.first_name, ac.branch_id, pl.paylevel_name, pl.annual_pay, ac.actual_pay
FROM accountant ac
INNER JOIN paylevel pl ON ac.paylevel_no = pl.paylevel_no
WHERE ac.actual_pay > pl.annual_pay
List the employees who are earning greater than or equal to the average amount of salary earned by employees belonging t

List the employees who are earning greater than or equal to the average amount of salary earned by employees belonging t


By : Andrew Drake
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further SELECT Fname, Lname, Salary,Dname
code :
SELECT Fname, Lname, Salary, Dname
FROM EMPLOYEE AS E1
LEFT JOIN DEPARTMENT AS D ON Dnumber = Dno
WHERE Salary >= (SELECT AVG(Salary) FROM EMPLOYEE AS E2 WHERE E2.Dno = E1.Dno)
ORDER BY Dname, Fname, Lname
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