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underscore groupBy inner key


underscore groupBy inner key

By : Budoy GMA
Date : October 24 2020, 08:10 AM
this one helps. I am trying to _.groupBy using a key inside one object of my collection. , Shorter/Best answer: _.groupBy(data, item => item.data.label);
code :


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Using underscore.js groupBy with Ember.js

Using underscore.js groupBy with Ember.js


By : panda
Date : March 29 2020, 07:55 AM
To fix the issue you can do You could implement your own groupBy function tailored for ember-data DS-ManyArray objects and extend _ with it:
code :
_.emberArrayGroupBy = function(emberArray, val) {
  var result = {}, key, value, i, l = emberArray.get('length'),
      iterator = _.isFunction(val) ? val : function(obj) { return obj.get(val); };

  for (i = 0; i < l; i++) {
    value = emberArray.objectAt(i);
    key   = iterator(value, i);
    (result[key] || (result[key] = [])).push(value);
  }
  return result;
};
var grouped = _.emberArrayGroupBy(activities, function(activity) {
  return activity.get('dateLabel');
});
var grouped = _.emberArrayGroupBy(activities, 'dateLabel');
_.groupBy = function(obj, val) {
  var result = {};
  var iterator = _.isFunction(val) ? val : function(obj) { return obj[val]; };
  each(obj, function(value, index) {
    var key = iterator(value, index);
    (result[key] || (result[key] = [])).push(value);
  });
  return result;
};
Underscore GroupBy Sort

Underscore GroupBy Sort


By : Rana Hesham
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I have a question regarding programming in function style. ,
sort it and convert backward to hash.
code :
var occurences = _.countBy([1, 2, 3, 4, 5], function(num) {
  return num % 2 == 0 ? 'even': 'odd';
});
// {odd: 3, even: 2}
var order = _.sortBy(_.keys(occurences), function(k){return occurences[k];})
// ["even", "odd"]
_.sortBy(_.pairs(occurences), 1)
// [["even", 2], ["odd", 3]]
Groupby without using underscore js

Groupby without using underscore js


By : user3821593
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , The problem with your original attempt is that you need to have two loops because in the first one newValue is an object not an array, so there is no reduce method on it.
The simpler solution is to use map (you could use forEach or $.each) and reduce in the second loop (I used simple for-in).
code :
var targetCollection = [{
    123456: [
        { "Id": "1", "name": "xxx", "age": "22" },
        { "Id": "1", "name": "yyy", "age": "15" },
        { "Id": "5", "name": "zzz", "age": "59" }
    ],
    789456: [
        { "Id": "1", "name": "xxx", "age": "22" },
        { "Id": "1", "name": "yyy", "age": "15" },
        { "Id": "5", "name": "zzz", "age": "59" }
    ]
}];

var result = targetCollection.map(function(obj) {
    for (var key in obj) {
        obj[key] = obj[key].reduce(function(prev, curr) {
            if (!prev[curr.Id]) prev[curr.Id] = [];
            prev[curr.Id].push(curr);
            return prev;
        }, {});
    }
    return obj;
});

document.write('<pre>' + JSON.stringify(result, null, 4) + '</pre>');
Underscore.js groupBy and Contains

Underscore.js groupBy and Contains


By : user3887807
Date : March 29 2020, 07:55 AM
I wish did fix the issue. I have two arrays of values one is needed to groupBy the other one so: , That was pretty easy thanks to the hint in the comment:
code :
_.groupBy(function (item) {
    if (item.country !== 'IT' && _.contains(countries, item.country)) {
        return 'IT';
    } else if (item.country === 'IT') {
        return 'UE';
    } else if (!_.contains(countries, item.country)) {
        return 'EXTRA-UE';
    }
});
Underscore.js groupBy two levels

Underscore.js groupBy two levels


By : Piglet2
Date : March 29 2020, 07:55 AM
I wish did fix the issue. I can't seem to word this properly by I need to group by date and foo: , This will give you the desired array.
code :
_.map(_.groupBy(list, 'date'), (value, key) => ({[key]: _.groupBy(value, 'foo')}))
var list = [{ date: "1", foo: "me", result: "meFoo" }, { date: "1", foo: "me2", result: "meYou" }, { date: "1", foo: "me3", result: "meHe" }, { date: "2", foo: "me", result: "meHim" }, { date: "2", foo: "me2", result: "meHim" }],
    grouped = _.map(_.groupBy(list, 'date'), (value, key) => ({[key]: _.groupBy(value, 'foo')}));

console.log(grouped);
.as-console-wrapper { max-height: 100% !important; top: 0; }
<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore-min.js"></script>
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