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Floating decimal point type in Haxe


Floating decimal point type in Haxe

By : Hung Nguyen Thanh
Date : October 23 2020, 08:10 PM
To fix the issue you can do I don't think anything like that exists in the standard library, apart from target-specific externs such as java.math.BigDecimal. So if you want a cross-platform solution, you would need a third-party library.
One that comes to mind is thx.Decimal from the thx.core library. Having a look at the associated test cases may be helpful since there's not much documentation.
code :


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Is SQL Server 'MONEY' data type a decimal floating point or binary floating point?

Is SQL Server 'MONEY' data type a decimal floating point or binary floating point?


By : SomeUser
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Neither. If it were an implementation of floating point it would be subject to the same inaccuracies as FLOAT and REAL types. See Floating Point on wikipedia.
MONEY is a fixed point type.
How to reliably format a floating point number to a specified number of decimal places in Haxe

How to reliably format a floating point number to a specified number of decimal places in Haxe


By : Kirill
Date : March 29 2020, 07:55 AM
it should still fix some issue I was wondering if there is a reliable way to convert a Float x in haxe to a String with a specified number of decimal places, e.g. 3.
code :
public static function floatToStringPrecision(n:Float, prec:Int){
  n = Math.round(n * Math.pow(10, prec));
  var str = ''+n;
  var len = str.length;
  if(len <= prec){
    while(len < prec){
      str = '0'+str;
      len++;
    }
    return '0.'+str;
  }
  else{
    return str.substr(0, str.length-prec) + '.'+str.substr(str.length-prec);
  }
}
Round floating point:Print exactly two digits after the decimal point rounded to the nearest decimal place

Round floating point:Print exactly two digits after the decimal point rounded to the nearest decimal place


By : parthibhan -
Date : March 29 2020, 07:55 AM
This might help you C or C++ don't care about what you need.
12.555 is not a binary floating point number. Binary floating point numbers are all integers multiplied by or divided by a power of two. 12.555 is not such a number. So when you write 12.555 then what you get is the floating-point number nearest to 12.555. Which may be smaller or larger than 12.555 and will be correctly rounded to 12.55 or correctly rounded to 12.56.
In MIPS Assembly, how do I truncate to two decimal places if I have a floating point value X.YZDEF in a floating point r

In MIPS Assembly, how do I truncate to two decimal places if I have a floating point value X.YZDEF in a floating point r


By : user3862283
Date : November 22 2020, 07:01 PM
This might help you You may want to look and see if these links will help you.
http://en.wikipedia.org/wiki/MIPS_architecture#MIPS_Assembly_Language
How to convert Decimal Floating-Point To 64-bit Hexadecimal using IEEE-754 Floating-Point convention

How to convert Decimal Floating-Point To 64-bit Hexadecimal using IEEE-754 Floating-Point convention


By : Parth Bhagat
Date : March 29 2020, 07:55 AM
Hope that helps If I understand your question correctly, you want to find the underlying binary representation of an IEEE 754 binary64-format floating-point number, and show that binary representation in hexadecimal.
For obtaining the underlying bits, the struct module is your friend. The struct.pack operation lets you interpret the 8 raw bytes underlying the binary64 representation as a (byte)string of length 8, and the struct.unpack operation will then let you re-interpret that string as a nonnegative integer (for example). Once you've got the integer, it's easy to find the hex representation. Here's a complete example for your data:
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