SQL first date for the first occurrence of a value

SQL first date for the first occurrence of a value

By : user2172485
Date : October 23 2020, 08:10 PM
I hope this helps you . I have a table with clients and the history of their rating (low, medium, high) which gets assessed quarterly. , Here's one way to tackle your problem:
code :

(111, 'high',  '20180930'  ), 
(111, 'high',  '20180630'  ) ,
(111, 'medium', '20180331' ) ,
(111, 'high',  '20171231'  ) ,
(111, 'high', '20170930'      ) ,
(111, 'low', '20170630'   ); 

    FROM #T

      C2.RATING AS C2Rating,
      C2.eff_From AS C2EffFrom,
LEFT JOIN CTE AS C2 ON C.RowNumb = C2.RowNumb - 1

SELECT ClientID, MAX (C2EffFrom) AS MaxEffFrom
WHERE RatingChanged = 1

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Mysql Find occurrence of start and end date range between two date columns

Mysql Find occurrence of start and end date range between two date columns

By : user3912915
Date : March 29 2020, 07:55 AM
I wish this help you From the above table, I will search between start and end date. For Ex., '2011-12-21' to '2011-12-23'. From the above image, 5th and 6th row will come under this date range. ie., 5th row will comprise of 21st and 22nd[2 dates] and 6th row comprise of 23rd[1 dates].
code :
    IF(DATEDIFF(least(validto, '2011-12-23'),
                greatest(validfrom, '2011-12-21')) >= 0,
       DATEDIFF(least(validto, '2011-12-23'),
                greatest(validfrom, '2011-12-21')) + 1,
       NULL) * rateperday
 ) as total
FROM thedata;
How Occurrence date of an event is different from the start date?

How Occurrence date of an event is different from the start date?

By : Juan José García Lóp
Date : March 29 2020, 07:55 AM
Get all uid that first occurrence in some date

Get all uid that first occurrence in some date

By : Iok-Lim Ng
Date : March 29 2020, 07:55 AM
it fixes the issue Let's say you have the following table: , Assuming you have the right indexes:
code :
select t.*
from t
where time >= '2016-07-19' and time < '2016-07-20' and
      not exists (select 1
                  from t t2
                  where t2.uid = t.uid and
                        t2.time < '2016-07-19'
select uid
from t
group by uid
having min(time) >= '2016-07-19' and min(time) < '2016-07-20';
Getting the date of the first occurrence of value

Getting the date of the first occurrence of value

By : yuzhenliu
Date : March 29 2020, 07:55 AM
it should still fix some issue I hope this is what you are looking for,
code :
T-SQL Grouping with LESS THAN {date} that breaks off on each occurrence of date

T-SQL Grouping with LESS THAN {date} that breaks off on each occurrence of date

By : Tama Solomon
Date : March 29 2020, 07:55 AM
With these it helps First - this is ignoring the question I raised in the comments above, and just allocates all rows to the expiry date on or after the use by date. You would need to rethink this if you need to split one use among multiple expiry dates
First, allocate an expiry date to each PointsUsed row. This is done by joining to all OrderPoints rows with an expiry date on or after the UseDate, then taking the minimum date.
code :
WITH allocatedPoints as 
    Select U.CustomerID, U.OrderPointsUsed, MIN(P.OrderPointsExpiry) as OrderPointsExpiry
    from CustomerOrderPointsUsed U 
    inner join CustomerOrderPoints P on P.CustomerID = U.CustomerID and P.OrderPointsExpiry >= U.OrderPointsUseDate
GROUP BY U.CustomerID, U.OrderPointsUseDate, U.OrderPointsUsed

Select P.CustomerID, P.OrderPoints, P.OrderPointsExpiry, 
    ISNULL(SUM(AP.OrderPointsUsed), 0) as used,
    P.OrderPoints - ISNULL(SUM(AP.OrderPointsUsed), 0) as remaining
from CustomerOrderPoints P
left outer join allocatedPoints AP on AP.CustomerID = P.CustomerID and AP.OrderPointsExpiry = P.OrderPointsExpiry
GROUP BY P.CustomerID, P.OrderPoints, P.OrderPointsExpiry
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