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How to number by group?


How to number by group?

By : user2172572
Date : October 23 2020, 08:10 AM
seems to work fine I want to add "seq" column as numbering by group which is organized with BSTN, ASTN, O and D. This work is hard to me to classify as another group within the group. A group is created whenever BSTN and O are equal, and ASTN and D are equal. , Here's a dplyr solution:
code :
library(dplyr)
df %>% group_by(BSTN, ASTN) %>%
    mutate(g = lag(D) != O,
           g = if_else(is.na(g), FALSE, g),
           seq = cumsum(g) + 1)
# A tibble: 21 x 6
# Groups:   BSTN, ASTN [2]
    BSTN  ASTN     O     D g       seq
   <int> <int> <int> <int> <lgl> <dbl>
 1   150   202   150   151 FALSE     1
 2   150   202   151   201 FALSE     1
 3   150   202   201   202 FALSE     1
 4   150   202   150   426 TRUE      2
 5   150   202   426   423 FALSE     2
 6   150   202   423   321 FALSE     2
 7   150   202   321   320 FALSE     2
 8   150   202   320   203 FALSE     2
 9   150   202   203   202 FALSE     2
10   150   403   150   426 FALSE     1
# ... with 11 more rows
df = read.table(text = "BSTN ASTN O D
150 202 150 151
150 202 151 201
150 202 201 202
150 202 150 426
150 202 426 423
150 202 423 321
150 202 321 320
150 202 320 203
150 202 203 202
150 403 150 426
150 403 426 423
150 403 423 321
150 403 321 320
150 403 320 403
150 403 150 151
150 403 151 201
150 403 201 403
150 403 150 426
150 403 426 422
150 403 422 205
150 403 205 403", header = T)


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How to fix procedure PL SQL Errors: 'not a single-group group function' & 'invalid number'

How to fix procedure PL SQL Errors: 'not a single-group group function' & 'invalid number'


By : Orestes
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , The reason you get an invalid-number error is in this part of your query:
code :
 TRIM(INITCAP(TO_CHAR(CP_MONTH, 'month')))
 TRIM(INITCAP(CP_MONTH))
SELECT some_column, COUNT(*) FROM some_table GROUP BY some_column
CURSOR CUR_DOGS (CP_MONTH VARCHAR2) IS
SELECT DR.DOG_NAME, TR.DOG_ID
FROM DOG DR, TRICK TR
WHERE TRIM(INITCAP(TO_CHAR(TR.DATE_OF_TRICK, 'month'))) = TRIM(INITCAP(CP_MONTH))
AND DR.DOG_ID = TR.DOG_ID
GROUP BY DR.DOG_NAME, TR.DOG_ID       -- Add this line
ORDER BY COUNT (TR.DOG_ID) DESC;
CURSOR CUR_DOGS (CP_MONTH VARCHAR2) IS
SELECT DR.DOG_NAME, TR.DOG_ID, COUNT (TR.DOG_ID) AS TRICK_COUNT
FROM DOG DR, TRICK TR
-- ... rest of query as before


-- ... later on ...
DBMS_OUTPUT.PUT_LINE (REC_DOGS.DOG_NAME ||' '||REC_DOGS.DOG_ID ||' '|| REC_DOGS.TRICK_COUNT);
Mysql Get Max Number of a group than make new group by that max number

Mysql Get Max Number of a group than make new group by that max number


By : Victor Peixoto
Date : March 29 2020, 07:55 AM
To fix this issue I have a table, it similar with this table
code :
select id, name, age, status 
    from thetable 
  where age = 
          (select max(age) 
              from thetable 
            where status="Life"
          )
  where status="Life"  
  order by id desc
Capture group certain number of times with regular expression but last group has remaining values

Capture group certain number of times with regular expression but last group has remaining values


By : OptimistPrime
Date : March 29 2020, 07:55 AM
will help you Given a string delimited by a colon and similar to this... , The solution using String.match and Array.slice functions:
code :
var str = "one:two:three:four:five:six:seven",
    groups = str.match(/([^:]+?):([^:]+?):(.+)?$/).slice(1);

console.log(groups);  // ["one", "two", "three:four:five:six:seven"]
Release a group when the number of messages in the group gets to a number defined in an another line message

Release a group when the number of messages in the group gets to a number defined in an another line message


By : IHaveProblemsCoding1
Date : March 29 2020, 07:55 AM
This might help you Would you mind to describe also how do you read from those 3 queues? It isn't clear to me where is a correlation between START and all those messages to the batch. If that is regular message-driven channel adapter, there is a case when we may start receiving those message but there is still no START or no info about count in the DB.
Anyway I'd make it like:
How to count number of rows per group greater than the average of that group in pandas group by?

How to count number of rows per group greater than the average of that group in pandas group by?


By : mrfazeli
Date : March 29 2020, 07:55 AM
Any of those help I have a data frame df and I use several columns from it to groupby: , You could also aggregate using a lambda function as the following:
code :
df.groupby(['col1', 'col2']).agg(['mean', 'count', 
                                  lambda x: (x > x.mean()).sum()])
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