Parse JSON to dataframe returns different numbers

Parse JSON to dataframe returns different numbers

By : Vijaya Kumbhar
Date : October 23 2020, 08:10 AM
Any of those help It looks like a rounding error to me, as you have an awful lot of digits. I guess in order to even show your data.frame you had to specify that you wanted a lot of digits, and in the documentation for ?print it says
"Note that for large values of digits, currently for digits >= 16, the calculation of the number of significant digits will depend on the platform's internal (C library) implementation of sprintf() functionality."
code :

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JSON.parse returns [object] from JSON

JSON.parse returns [object] from JSON

By : Marvin
Date : March 29 2020, 07:55 AM
wish help you to fix your issue The reason why it appears as [Object] is for readability, if you want to show a full dump of the results, you have to pass it through JSON.stringify first.
As to access the address_components, the results is an array, so you'll have to access them for a specific element of that array (e.g. gmaps.results[0].address_components)
Parse JSON to a dataframe

Parse JSON to a dataframe

By : Anthony Jude De-Gol
Date : March 29 2020, 07:55 AM
Hope that helps Not sure how to do this:
code :

x <- fromJSON('[
  "MULTIPOLYGON (((-95.0000000372529 40.999989970587194, -94.5000000372529 40.999989970587194, -94.5000000372529 40.499989970587194, -95.0000000372529 40.499989970587194)))"

map(x, st_as_sfc) %>%
## [[1]]
##      X1       X2
## 1 -95.0 40.99999
## 2 -94.5 40.99999
## 3 -94.5 40.49999
## 4 -95.0 40.49999
  "MULTIPOLYGON (((-95.0000000372529 40.999989970587194, -94.5000000372529 40.999989970587194, -94.5000000372529 40.499989970587194, -95.0000000372529 40.499989970587194)))"
json.parse returns Unexpected token o in JSON at position 1

json.parse returns Unexpected token o in JSON at position 1

By : Count
Date : March 29 2020, 07:55 AM
will be helpful for those in need var parsed = JSON.parse(xhr); tries to parse the XMLHttpRequest object. That will trigger converting the object to a string and then trying to parse that string as JSON, yielding "[object Object]", which is invalid JSON as of the o.
You probably wanted:
code :
var parsed = JSON.parse(xhr.responseText);
document.getElementById('test').innerHTML = parsed.articles[0].description;
How to parse a JSON which has only numbers

How to parse a JSON which has only numbers

By : Sata
Date : March 29 2020, 07:55 AM
hop of those help? You should probably use nested for loops.. what exactly you should print depends on how you expect your output to look.. but you could try this:
code :
#!/usr/bin/env python3
import json

data = '{"297050": [[12, 137], [193, 776]], "297056": [[12, 203]]}'

data = json.loads(data)

for k, v in data.items():
    for list_of_ints in v:
        for integer in list_of_ints:
#!/usr/bin/env python3
import json

output = "For entry {} this is the list {}"
data = '{"297050": [[12, 137], [193, 776]], "297056": [[12, 203]]}'

data = json.loads(data)

for k, v in data.items():
    lists_with_commas = ", ".join([str(x) for x in v])
    print(output.format(k, lists_with_commas), end=" ")
For entry 297050 this is the list [12, 137], [193, 776] For entry 297056 this is the list [12, 203]
Generic way to Parse Spark DataFrame to JSON Object/Array Using Spray JSON

Generic way to Parse Spark DataFrame to JSON Object/Array Using Spray JSON

By : user3279187
Date : March 29 2020, 07:55 AM
this one helps. After trying various approach using various libraries, I finally settled with the below simple approach.
code :
val list = sc.parallelize(List(("a1","b1","c1","d1"),("a2","b2","c2","d2"))).toDF

val jsonArray = list.toJSON.collect
/*jsonArray: Array[String] = Array({"_1":"a1","_2":"b1","_3":"c1","_4":"d1"}, {"_1":"a2","_2":"b2","_3":"c2","_4":"d2"})*/

val finalOutput = jsonArray.mkString("[", ",", "]")

/*finalOutput: String = [{"_1":"a2","_2":"b2","_3":"c2","_4":"d2"},{"_1":"a1","_2":"b1","_3":"c1","_4":"d1"}]*/
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