Graph dictionary

Graph dictionary

By : Sheetal Ganeshgudi
Date : October 23 2020, 08:10 AM
wish help you to fix your issue It seems like this might be easier to understand as a simple dictionary comprehension:
code :
> A=[[1, 0, 0], [0, 0, 0], [0, 1, 1]]
> {row:[col for col, included in enumerate(cols) if included ] for row, cols in enumerate(A)}

{0: [0], 1: [], 2: [1, 2]}
adj = {}

for index, row in enumerate(A):
    adj[index] =  []
    for e_index, edge in enumerate(row):
        if edge:

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Flattening a dictionary representing a graph into a dictionary of lists

Flattening a dictionary representing a graph into a dictionary of lists

By : 2k1dmg
Date : March 29 2020, 07:55 AM
this one helps. This does not produce the output which is formatted 'exactly' as you asked for, but hopefully it is close enough to be usable.
code :
def flatten_dict(in_dict):
    in_dict_keys = in_dict.keys()
    in_dict_values = in_dict.values()
    in_dict_values_list = []
    for value1 in in_dict_values:
        for value2 in value1:
    flattenned_dict = in_dict.copy()

    "create new dict with 'substtitutions'"
    for key in in_dict_keys:
        for i, value in enumerate(in_dict[key]):
            if value in in_dict_keys:
                flattenned_dict[key][i] = {value:in_dict[value]}
    "clean up new dict"
    for value in in_dict_values_list:
        if value in flattenned_dict:
            del flattenned_dict[value]

    return flattenned_dict

if __name__ == "__main__":
    input1 = {'1': ['2', '3', '4'],'2': ['5', '6', '7'],'3': ['8', '9', '10'],}
    input2 = {'1': ['2', '3', '4'],'2': ['5', '6', '7'],'3': ['8', '9', '10'],'7': ['11', '12']}
    flattenned_dict = flatten_dict(input2)
How to graph a python frequency dictionary?

How to graph a python frequency dictionary?

By : Baboo Gee
Date : March 29 2020, 07:55 AM
I wish this helpful for you I'd suggest using matplotlib.
Using a histogram is the easiest way to do this, but plt.hist(a) requires a to be a list.
code :
plt.bar(odict.keys(), odict.values(), width)
Using a dictionary to plot graph in D3.js

Using a dictionary to plot graph in D3.js

By : user3698438
Date : March 29 2020, 07:55 AM
this will help I have a dictionary of the form: , Assuming that your data is in the format:
code :
[{'2019-10': 273}, {'2019-11': 299}, {'2019-12': 244}, {'2020-01': 231}, {'2020-02': 232}]
var height = 200;
var width = 400;

var data = [{'2019-10': 273}, {'2019-11': 299}, {'2019-12': 244}, {'2020-01': 231}, {'2020-02': 232}];

var mapped = data.map(d => {
  return {
    date: Object.keys(d)[0],
    count: d[Object.keys(d)[0]]

var x = d3.scale.ordinal().rangeRoundBands([0, width], .05);
var y = d3.scale.linear().range([height, 0]);

x.domain(mapped.map(d => d.date));
y.domain([0, d3.max(mapped, d => d.count)]);
var svg = d3.select("#simple").append("svg")
    .attr("width", width)
    .attr("height", height);

      .style("fill", "steelblue")
      .attr("x", d => x(d.date))
      .attr("width", x.rangeBand())
      .attr("y", d => y(d.count))
      .attr("height", d => height - y(d.count));
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.5.17/d3.min.js"></script>
<div id="simple"></div>
creating a graph of dictionary data?

creating a graph of dictionary data?

By : user3709009
Date : March 29 2020, 07:55 AM
should help you out There's no reason you can't plot a dictionary, using .keys() and .values(). Here's an example showing a horizontal barchart (I chose this orientation so the team names are readable on the Y-axis). It's based on a simple horizontal barchart example on Pythonspot.com.
code :
import matplotlib.pyplot as plt
import numpy as np

def plot_wins(data):
    teams = data.keys()
    wins = data.values()
    y_pos = np.arange(len(teams))

    plt.barh(y_pos, wins, align='center', alpha=0.5)
    plt.yticks(y_pos, teams)
    plt.title('Superbowl Wins by Team')

plot_wins({ 'Philadelphia Eagles': 1, 'New England Patriots': 5, ..etc..})
Create graph-tool Graph from dictionary

Create graph-tool Graph from dictionary

By : Sajid Ali
Date : March 29 2020, 07:55 AM
will be helpful for those in need This looks quite simple. Assuming that your dictionary represents an adjacency list of the graph (that is what you said in the comment), it can be done as follows:
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