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Suggestion on picking the best options of two lists (minimum and maximum )python


Suggestion on picking the best options of two lists (minimum and maximum )python

By : Kanika D
Date : October 22 2020, 08:10 PM
help you fix your problem I have three lists, each list has 200,000 item. The first list titled 'config' is a list of configuration names (these are window blind configuration). The second list has the illuminance performance of each configuration (same order, meaning that config_a001 yields illuminance value of 350). The last list has a value for each config (same order as well, so config_002 has a value of 0.24) , You might consider organizing the data into a pandas DataFrame:
code :
import pandas as pd

config = ['config_a001', 'config_a002', 'config_a003', 'config_a004', 'config_a005', 'config_a006']
il = [350, 376, 310, 340, 290, 375]
lur = [0.3, 0.24, 0.21, 0.31, 0.24, 0.28]
d = {'config': config, 'il': il, 'lur': lur}
df = pd.DataFrame(d)
res = df.sort_values(['il', 'lur'], ascending=[False, True])[:5]['config'].values
list(res)
# Result: ['config_a002', 'config_a006', 'config_a001', 'config_a004', 'config_a003']


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Maximum value and Minimum value from list of lists python 2.7

Maximum value and Minimum value from list of lists python 2.7


By : Reevon
Date : March 29 2020, 07:55 AM
around this issue Here's a way to calculate the result for each inner list and then store each inner-list's result as a dictionary inside a list - one dictionary per inner-list.
code :
max_and_min = []  # This will contain a dictionary per inner list

for inner_list in odds_list:
    lefts = [x[0] for x in inner_list]
    rights = [x[1] for x in inner_list]

    result_dict = {'max_left': max(lefts), 'min_left': min(lefts), 'max_right': max(rights), 'min_right': min(rights)}
    max_and_min.append(result_dict)

# Get the result dict for the first inner list
print(max_and_min[0])
Divide a list into two lists one from minimum to maximum and the other from maximum to minimum

Divide a list into two lists one from minimum to maximum and the other from maximum to minimum


By : Cooy
Date : March 29 2020, 07:55 AM
I wish this helpful for you I have two lists as given below; , Starting from the following data:
code :
phi= ['0','pi/4', 'pi/2','3*pi/4', 'pi','5*pi/4','3*pi/2','7*pi/4', '2*pi']
t = [1,1.25,1.50,1.25,1,0.75,0.5,0.5,0.75]
max_index = np.argmax(t)
min_index = np.argmin(t)
# the +1 in some indexes is to have pi/2 and 3pi/2 in both phi1 and phi2
phi1 = phi[min_index:]+phi[:max_index+1]
t1 = t[min_index:]+t[:max_index+1]
phi2 = phi[max_index:min_index+1]
t2 = t[max_index:min_index+1]
# Out: t1, phi1
# [0.5, 0.5, 0.75, 1, 1.25, 1.5] ['3*pi/2', '7*pi/4', '2*pi', '0', 'pi/4', 'pi/2']
# t2,phi2
# [1.5, 1.25, 1, 0.75, 0.5] ['pi/2', '3*pi/4', 'pi', '5*pi/4', '3*pi/2']
max_val = max(t)
min_val = min(t)
max_index = t.index(max_val)
min_index = t.index(min_val)
Find minimum and maximum value at each index of a dictionary of lists

Find minimum and maximum value at each index of a dictionary of lists


By : Alex Kralin
Date : March 29 2020, 07:55 AM
I hope this helps . I have a dictionary having following structure , You may use zip with min and max:
code :
dct = {'key1': [1,2,3,4,5], 'key2': [2,0,4,5,6]}

[min(i) for i in zip(*dct.values())]
[max(i) for i in zip(*dct.values())]
[1, 0, 3, 4, 5]
[2, 2, 4, 5, 6]
min_list, max_list = map(list, zip(*[(min(i), max(i)) for i in zip(*dct.values())]))

min_list
[1, 0, 3, 4, 5]

max_list
[2, 2, 4, 5, 6]
dct = {1: [], 2: []}
[([2, 0, 4, 5, 6],), ([1, 2, 3, 4, 5],)]
[(2, 1), (0, 2), (4, 3), (5, 4), (6, 5)]
Calculating minimum or maximum by index in list of lists

Calculating minimum or maximum by index in list of lists


By : AJ_R
Date : March 29 2020, 07:55 AM
hope this fix your issue This is one way you can structure your logic via a dispatcher dictionary and a couple of list comprehensions:
code :
list_of_elements = [1255, 1256, 1257, 1258, 1259]

# extract data via list comprehension
L = [components[i] for i in list_of_elements]

# defined explicitly for demonstration
L = [[481, 498, 5142, 5157], [481, 497, 5192, 5199],
     [481, 498, 5219, 5238], [481, 484, 5239, 5242],
     [481, 487, 5269, 5271]]

from operator import itemgetter

# define dispatcher dictionary
funcs = {0: min, 1: max}

# apply via list comprehension
res = [funcs[i%2](map(itemgetter(i), L)) for i in range(len(L[0]))]

print(res)

[481, 498, 5142, 5271]
Finding minimum, maximum and average values for nested lists?

Finding minimum, maximum and average values for nested lists?


By : Sidney van de Stouwe
Date : March 29 2020, 07:55 AM
With these it helps So I have these lists: , Highest value:
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