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Laravel, convert to uuid text from uuid binary upon creating model


Laravel, convert to uuid text from uuid binary upon creating model

By : user2172760
Date : October 22 2020, 08:10 PM
like below fixes the issue The library you are using is optimizing the UUID by storing it as binary. Using the same library to store it as text would be working against its purpose. There shouldn't be any reason for you to store it as text because the library is making all the conversions for you.
For example, if you wanted to use the UUID in a URL or JSON, the library can convert from binary to text for you.
code :
$model = MyModel::create();
dump($model->uuid_text); // "6dae40fa-cae0-11e7-80b6-8c85901eed2e" 


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UUID primary key in Eloquent model is stored as uuid but returns as 0

UUID primary key in Eloquent model is stored as uuid but returns as 0


By : Jacek Fila
Date : March 29 2020, 07:55 AM
hop of those help? Nevermind, I found the answer after searching through the docs: https://laravel.com/docs/5.2/eloquent#eloquent-model-conventions
Under the section "Primary Keys" there's a little blurb:
code :
class UuidModel extends Model
{

    public $incrementing = false;

    /**
     * Sets the UUID value for the primary key field.
     */
    protected function setUUID()
    {
        $this->id = preg_replace('/\./', '', uniqid('bpm', true));
    }
}
How can I convert binary UUID to UUID in scala?

How can I convert binary UUID to UUID in scala?


By : 陈艾冰
Date : March 29 2020, 07:55 AM
To fix the issue you can do I'm reading data from Hbase using spark and the UUID in Hbase is in binary format and I want to convert that binary type of UUID into regular UUID in scala. Anyone know how can it be done? , Below is the code for resolving the question.
code :
def touuid(a: Array[Byte]): String = 
{
  val bb   = ByteBuffer.wrap(a)
  val high = bb.getLong();
  val low  = bb.getLong();
  val uuid = new UUID(high, low);
  return uuid.toString()
}

val havid = udf((x: Array[Byte]) => touuid(x))
Webpatser/Laravel-UUID throwing exception at line 118 despite correct UUID generation

Webpatser/Laravel-UUID throwing exception at line 118 despite correct UUID generation


By : 許又中
Date : March 29 2020, 07:55 AM
I wish this helpful for you Turns out, both strlen and mb_strlen function oddly when calculating $uuid's length (even though var_dump'ing it returns string(16) as it should, the aforementioned functions provide a value between 11 and 13 during tests.
What I did is change the condition to strlen($uuid) > 16 which still results in correct UUID generation, and doesn't throw (in my opinion) silly exceptions.
symfony4, FOSRestBundle and ramsey/uuid-doctrine - convert uuid object to string for REST API

symfony4, FOSRestBundle and ramsey/uuid-doctrine - convert uuid object to string for REST API


By : Lady Fartalot
Date : March 29 2020, 07:55 AM
hop of those help? I solved it by myself now.
I just need to change the column type of the field from
code :
/**
 * @var UuidInterface
 *
 * @ORM\Id()
 * @ORM\Column(type="uuid", unique=true)
 * @ORM\GeneratedValue(strategy="CUSTOM")
 * @ORM\CustomIdGenerator(class="Ramsey\Uuid\Doctrine\UuidGenerator")
 */
private $id;
/**
 * @var string
 *
 * @ORM\Id()
 * @ORM\Column(type="string", unique=true, length=36)
 * @ORM\GeneratedValue(strategy="CUSTOM")
 * @ORM\CustomIdGenerator(class="Ramsey\Uuid\Doctrine\UuidGenerator")
 */
private $id;
Go: convert reflect.Value of type uuid.UUID (satori) back to uuid.UUID again

Go: convert reflect.Value of type uuid.UUID (satori) back to uuid.UUID again


By : Krieglied
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Use a type assertion on the underlying value:
code :
u, ok := reflectedValue.Interface().(uuid.UUID)
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