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How to extract the trailing digits from a string in R?


How to extract the trailing digits from a string in R?

By : Kirthi Deva
Date : October 22 2020, 08:10 PM
To fix the issue you can do I have a column of data that looks like this: , In case you always have the Q1#_ string, you can do:
code :
gsub("Q1#_", "", df$varX)


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How do I remove trailing digits fitting a pattern from a string in C#?

How do I remove trailing digits fitting a pattern from a string in C#?


By : Joelk
Date : March 29 2020, 07:55 AM
like below fixes the issue First you should trim end of string, and then get a required substring:
code :
var tmp = str.TrimEnd('0');
var result = tmp.Substring(Math.Max(0,tmp.Length - 6));
How to strip trailing digits from a string

How to strip trailing digits from a string


By : Vincent Mark Leon De
Date : March 29 2020, 07:55 AM
seems to work fine I have a variable text whose value is like below,I need strip of trailing digits,is there a python built-in function to do it..if not,please suggest how can this be done in python , You can use rstrip. Check the python docs.
Extract first digit sequence from string containing digits, non-digits and then digits

Extract first digit sequence from string containing digits, non-digits and then digits


By : user2392561
Date : March 29 2020, 07:55 AM
I wish this help you Use str.extract with regex \d for extract digits, {,5} means first 5 digits and + is for all digits:
code :
df['first_5_digits'] = df['Col'].str.extract('(\d{,5})')
df['all_digits'] = df['Col'].str.extract('(\d+)')
print (df)
                       Col first_5_digits all_digits
0              111042345--          11104  111042345
1                111042345          11104  111042345
2    110374217dclid=CA-R3K          11037  110374217
3  109202817lciz@MM10082IA          10920  109202817
df['first_5_digits'] = df['Col'].str.extract('(\d+)').str[:5]
Extract days digits present in string and find days digits between extracted days digits in r

Extract days digits present in string and find days digits between extracted days digits in r


By : Radovan Heldák
Date : October 13 2020, 08:00 AM
I wish did fix the issue. Try the following.
The main function is seqDigits. It starts by getting a list of vectors, each of them with the digits between the strings "between day" and "of the month". Then it produces the sequences of digits with Reduce/':' and outputs them sorted.
code :
auxfun <- function(s){
  f <- function(.s){
    m <- gregexpr("\\d+", .s)
    regmatches(.s, m)
  }
  m <- gregexpr("between day \\d+ and \\d+ of the month", s)
  s <- regmatches(s, m)
  sapply(unlist(s), f)
}

seqDigits <- function(X){
  y <- auxfun(X)
  d <- lapply(y, function(x){
    Reduce(':', as.numeric(x[2]), as.numeric(x[1]))
  })
  sort(unname(unlist(d)))
}

seqDigits(strng1)
# [1]  1  2  3  4  5  6  7  8  9 10 11 12 13 14 26 27 28 29 30 31
seqDigits(strng2)
# [1] 14 15 16 17 18 19 20 21 22 23 24 25 26
I need to extract the first 6 digits and the last 4 digits of numbers in a string and delete leading zeros of the same w

I need to extract the first 6 digits and the last 4 digits of numbers in a string and delete leading zeros of the same w


By : Vickytech
Date : October 04 2020, 02:00 PM
wish helps you I need to delete leading zeros and extract the first 6 digits and the last 4 digits of numbers in a string with regular expression. , You could use this regex: /^0*(\d{6})\d*?(\d{4})$/
Explanation:
code :
function extractNumber(numberStr) {
  let match = numberStr.match(/^0*(\d{6})\d*?(\d{4})$/);
  return `${match[1]}${match[2]}`;
}

console.log(extractNumber('00005598001400248980'));
console.log(extractNumber('00000377820202008104'));
function extractNumber(numberStr, firstN = 6, lastN = 4) {
  let regex = new RegExp(`^0*(\\d{${firstN}})\\d*?(\\d{${lastN}})$`);
  let match = numberStr.match(regex);
  return `${match[1]}${match[2]}`;
}

console.log(extractNumber('00005598001400248980'));
console.log(extractNumber('00000377820202008104', 5));
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