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Two values in the same column


Two values in the same column

By : David
Date : October 22 2020, 08:10 AM
Hope this helps I have two columns with different values: , Do you mean like this
code :
echo '<tr>
        <td scope="row">' . $row["id"].'</td>
        <td>' . $row["data"] . '(' . $row["ip"] . ')</td>
      </tr>';


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Google Apps Script: How to pull values from column A based on values in column E and send all values in one email?

Google Apps Script: How to pull values from column A based on values in column E and send all values in one email?


By : user2004913
Date : March 29 2020, 07:55 AM
wish helps you First set up variables to keep track of which student did not show up:
code :
var students = [];
var student_rows = [];
if (status == statusArray[i][4] & emailSent != EMAIL_SENT) {
  var student = statusArray[i][0];
  students.push(student);
  student_rows.push(i+1);
}
var body    = "This is a No-Show Report for " + students.join(', ') + " from " + class;
var subject = "No-Show Report for " + students.join(', ') + " from " + class;
MailApp.sendEmail(email,subject,body,{NoReply : true});
for (var i=0; i<student_rows.length; i++) {
  sheet.getRange(student_rows[i], 85).setValue(EMAIL_SENT);
  SpreadsheetApp.flush();
}
function Email_ReminderNS() {

  var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("July_August"),
      EMAIL_SENT = "EMAIL_SENT",
      statusArray = sheet.getDataRange().getValues();
  var class = statusArray[0][8], 
      status = "X",
      email   = "francis@bposolutions.com";

  var students = [];
  var student_rows = [];

  for (i=7;i < statusArray.length;i++){
    var emailSent = statusArray[i][84];

    if (status == statusArray[i][4] & emailSent != EMAIL_SENT) {
      var student = statusArray[i][0];
      students.push(student);
      student_rows.push(i+1);
    }
  }

  var body    = "This is a No-Show Report for " + students.join(', ') + " from " + class;
  var subject = "No-Show Report for " + students.join(', ') + " from " + class;
  MailApp.sendEmail(email,subject,body,{NoReply : true});

  for (var i=0; i<student_rows.length; i++) {
    sheet.getRange(student_rows[i], 85).setValue(EMAIL_SENT);
    SpreadsheetApp.flush();
  }
}
R convert Datatable distinct column values to column names and column values as values from another column

R convert Datatable distinct column values to column names and column values as values from another column


By : DangerH
Date : March 29 2020, 07:55 AM
Hope that helps We can use acast to convert from 'long' to 'wide' format. The resulting dataset will be a matrix.
code :
library(reshape2)
acast(df1, Column_Two~Column_One, value.var="Column_Three")
#   A   B   C
#1  4  44  43
#2  3  32 310
#3 77 770  68
 lst <- lapply(split(df2[-1], df2$Column_Zero), function(x) 
         acast(x, Column_Two~Column_One,value.var="Column_Three"))

lst
#$XX
#   A   B   C
#1  4  44  43
#2  3  32 310
#3 77 770  68

#$YY
#  A1  B1  C1 D2
#1  4  44  43  4
#2  3  32 310  5
#3 77 770  68  6
Hive- alter a column values and insert new values in place of old column values in the table

Hive- alter a column values and insert new values in place of old column values in the table


By : Jason Chen
Date : March 29 2020, 07:55 AM
I wish this helpful for you I am newbie in Hive. I have a table in Hive with Unix timestamp values in a column. I am trying to alter the column values with normal timestamp values. , Because correct syntax is:
code :
ALTER TABLE name CHANGE column_name new_name new_type
MySQL update a column's values to equal the sum of another column's values based on date and another column's value

MySQL update a column's values to equal the sum of another column's values based on date and another column's value


By : user1961602
Date : March 29 2020, 07:55 AM
I wish this helpful for you You need SUM() aggregation with Group By on team and game_date:
code :
SELECT 
  team, 
  game_date, 
  SUM(minutes) AS team_minutes_played 
FROM 
  your_table_name 
GROUP BY 
  team, 
  game_date 
Update values in a column based on values of another data frame's column values in PySpark

Update values in a column based on values of another data frame's column values in PySpark


By : user1968146
Date : March 29 2020, 07:55 AM
I wish this helpful for you
The first thing you want to do is explode the values in df2.items2 so that contents of the arrays will be on separate rows:
code :
from pyspark.sql.functions import explode
df2 = df2.select(explode("items2").alias("items2"))
df2.show()
#+------+
#|items2|
#+------+
#|     B|
#|     A|
#|     C|
#|     E|
#+------+
from pyspark.sql.functions import expr, collect_list

df1.alias("l").crossJoin(df2.alias("r"))\
    .where(expr("array_contains(l.items1, r.items2)"))\
    .groupBy("l.id1", "l.items1")\
    .agg(collect_list("r.items2").alias("items1_updated"))\
    .show()
#+---+---------------+--------------+
#|id1|         items1|items1_updated|
#+---+---------------+--------------+
#|  1|      [E, A, C]|     [A, C, E]|
#|  0|   [B, C, D, E]|     [B, C, E]|
#|  4|[A, C, E, B, D]|  [B, A, C, E]|
#|  3|      [E, G, A]|        [A, E]|
#|  2|   [F, A, E, B]|     [B, A, E]|
#+---+---------------+--------------+
df1.withColumn("items1", explode("items1")).alias("l")\
    .join(df2.alias("r"), on=expr("l.items1=r.items2"), how="left")\
    .groupBy("l.id1")\
    .agg(
        collect_list("l.items1").alias("items1"),
        collect_list("r.items2").alias("items1_updated")
    ).show()
#+---+---------------+--------------+
#|id1|         items1|items1_updated|
#+---+---------------+--------------+
#|  0|   [E, B, D, C]|     [E, B, C]|
#|  1|      [E, C, A]|     [E, C, A]|
#|  3|      [E, A, G]|        [E, A]|
#|  2|   [F, E, B, A]|     [E, B, A]|
#|  4|[E, B, D, C, A]|  [E, B, C, A]|
#+---+---------------+--------------+
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