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C# similar bitwise operations resulting in different answers


C# similar bitwise operations resulting in different answers

By : Defy
Date : October 22 2020, 08:10 AM
I hope this helps . I'm going to interpret this question as one about the order of the bits because, as comments suggest, it doesn't make much sense to expect different operations on the same data to return the same result, in most cases.
So why are we starting with 128 and shifting right instead of starting with 1 and shifting left? Both methods would be valid for enumerating through each bit within the byte, but they operate in reverse order.
code :


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Why were bitwise operations slightly faster than addition/subtraction operations on older microprocessors?

Why were bitwise operations slightly faster than addition/subtraction operations on older microprocessors?


By : Junaid
Date : March 29 2020, 07:55 AM
it helps some times In any binary bitwise operation, each output bit depends only on the two corresponding bits in the inputs. In an add operation, each output bit depends on the corresponding bits in the inputs and all the bits to the right (toward lower values).
For example, the leftmost bit of 01111111 + 00000001 is 1, but the leftmost bit of 01111110 + 00000001 is 0.
What are the advantages to using bitwise operations over boolean operations in Python?

What are the advantages to using bitwise operations over boolean operations in Python?


By : ptls44
Date : March 29 2020, 07:55 AM
will help you If you want a concrete example of bitwise operators being used in the standard library, just look at the re library. According to the API, the flags are supposed to be bitwise ORed together.
This allows you to pass a large number of options in a single argument. Consider the following options:
code :
re.compile(expression,re.I | re.M | re.X)
re.compile(expression,ignorecase=True,multiline=True,verbose=True)
Bitwise operations in Java give different value with similar code?

Bitwise operations in Java give different value with similar code?


By : Juan Carlos Linares
Date : March 29 2020, 07:55 AM
Any of those help Short question. I am quite new to doing bit/bytewise operations in Java, but I noticed something strange.
code :
(index = nodes.length - 1) & hash
index = (nodes.length - 1) & hash
C Bitwise operations left shift and bitwise OR

C Bitwise operations left shift and bitwise OR


By : user2142331
Date : March 29 2020, 07:55 AM
help you fix your problem a breakdown:
every left shift operation on a binary number effectively multiplies it by 2 0111(7) << 1 = 1110(14) consider rhubarbdog answer - the operation can be seen as two separate actions. first left-shift (multiply by two) and then OR with the current bit being reviewed the PC does not distinguish between the value displayed and the binary representation of the number
code :
bits = {0, 1, 0, 1};
count = 4;
unsigned binary_array_to_numbers(const unsigned *bits, size_t count) {
    unsigned res = 0;
    for (size_t i = 0; i < count; i++)
        res = res << 1 // (a)
        res = res | bits[i]; /* (b) according to rhubarbdog answer */
    return res;
}
C/C++ Bitwise Operations not resulting in expected output?

C/C++ Bitwise Operations not resulting in expected output?


By : user2504713
Date : March 29 2020, 07:55 AM
Hope this helps
Is there something incorrect about the way I am trying to process bit shifting in my head?
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