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Javascript - issues with regex expression


Javascript - issues with regex expression

By : Fahad Karim
Date : October 22 2020, 08:10 AM
fixed the issue. Will look into that further I have a string that should be validated to be in the form of something like "Readdata.v5". What I do in my code, is I split the string based on the . (I check to make sure there is exactly one . in the string, so all other cases are handled). I want to validate it so that the first part of the string follows the format of a phrase, followed by any character to the period. The second part should start with the char v and then be followed by any number. This is the regex I have so far: , You can use this
code :
^"(Create|Read|Update|Delete)[a-zA-Z]*\.v\d+"$


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Javascript URL Regex issues

Javascript URL Regex issues


By : user3297508
Date : March 29 2020, 07:55 AM
it helps some times It's because the ^ character at the beginning of the expression means "match the beginning of the string" (in other words, what you have is a starts-with search). Remove that and it will match anywhere in the test string.
code :
var re = /(http[s]?:\/\/){0,1}(www\.){0,1}[a-zA-Z0-9\.\-]+\.[a-zA-Z]{2,5}[\.]{0,1}/;
facing issues while creating REGEX expression

facing issues while creating REGEX expression


By : Алексей Смиян
Date : March 29 2020, 07:55 AM
this one helps. I am trying to create regex experssion which can replace only ',' only at the end or start of the string with '' , Use ^, and $ to match only at the beginning or at the end:
code :
/^,|,$/
'Sunday,Monday'.replace(/^,|,$/g, '') // => "Sunday,Monday"
'Sunday,'.replace(/^,|,$/g, '')       // => "Sunday"
',Monday'.replace(/^,|,$/g, '')       // => "Monday"
Javascript Regular Expression (exp)? issues

Javascript Regular Expression (exp)? issues


By : KhYamini
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Your regular expression includes the part [,] which translates as "must contain a comma in that position".
If the comma is indeed required then [21] will not evaluate but [21,] will.
Javascript Regex match expression inside expression? (SUM\(.*?\))

Javascript Regex match expression inside expression? (SUM\(.*?\))


By : cbDallasTx
Date : March 29 2020, 07:55 AM
Hope that helps SUM\([0-9\;]+\)? this regex would show you every SUM expression without the need of enclosing paranthesis.
Code:
code :
let data = "SUM(1;2;SUM(999);SUM(3;4);SUM(9))";
let match = data.match(/SUM\([0-9\;]+\)?/gm)
["SUM(1;2;", "SUM(999)", "SUM(3;4)", "SUM(9)"]
let data = "SUM(1;2;SUM(999);SUM(3;4);SUM(9))";
let match = data.match(/SUM\([0-9\;]+\)?/gm).map(r => r.slice(-1) === ")" ? r : r.concat(")"))
["SUM(1;2;)", "SUM(999)", "SUM(3;4)", "SUM(9)"]
Regex for a string including one expression and excluding another issues

Regex for a string including one expression and excluding another issues


By : Jenny
Date : March 29 2020, 07:55 AM
I hope this helps . You are looking for ^((?!and).)*Cord((?!and).)*$ I used does not contain and on both sides of cord since and might come before or after cord.
You can do:
code :
a[!grepl("^((?!and).)*Cord((?!and).)*$",a,ignore.case = T,perl=T)]
[1] "https://www.homedepot.com/p/Champion-Power-Equipment-7500-Watt-Gasoline-Powered-Electric-Start-Portable-Generator-and-25-ft-Extension-Cord-100219/206268632"
grep("^((?!and).)*Cord((?!and).)*$",a,ignore.case = T,perl=T,invert = T,value = T)
[1] "https://www.homedepot.com/p/Champion-Power-Equipment-7500-Watt-Gasoline-Powered-Electric-Start-Portable-Generator-and-25-ft-Extension-Cord-100219/206268632"
 a = rep(a,1000)
 microbenchmark::microbenchmark(
    a=grepl("^((?!and).)*Cord((?!and).)",a,ignore.case = T,perl=T),
    b=grepl("^(?:(?!and).)*Cord(?:(?!and).)",a,ignore.case = T,perl=T)
  )
Unit: milliseconds
 expr      min       lq     mean   median       uq      max neval cld
    a 8.604448 8.631186 8.693752 8.656785 8.716235 9.077194   100   b
    b 7.915523 7.944821 7.999503 7.967861 7.998580 9.221692   100  a
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