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Subset rows based on "start and stop" strings


Subset rows based on "start and stop" strings

By : user2173193
Date : October 21 2020, 08:10 PM
hop of those help? You can lookup where a value is with the function which, and use that as in index to get the values you are looking for. If you want everything from the first to the second "c", it would look like this:
code :
indices <- which(df$X1=='c')
range <- indices[1]:indices[2]
df$X2[range]


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Calling "start" to start program and "stop" to close current instance in C

Calling "start" to start program and "stop" to close current instance in C


By : JeverPils
Date : March 29 2020, 07:55 AM
like below fixes the issue You will always run a separate process when running it with 'stop' argument. You need to find the running daemon and sending it a signal to stop it. When your deamon is started (option 'start'), you might want to store its pid somewhere so that when it is started with 'stop' option, it can retrieve the pid of the daemon and send it a signal to stop it. You can also parse the process table to find your daemon, but that will be more complex.
Filter rows based on variables "beginning with" strings specified by vector

Filter rows based on variables "beginning with" strings specified by vector


By : Tuesday
Date : March 29 2020, 07:55 AM
this one helps. You can make a regex pattern from the interest vector and apply it to each column of your data frame except for the patient id, use rowSums to check if there is any var in a row match the pattern:
code :
library(dplyr)
pattern = paste("^(", paste0(dx, collapse = "|"), ")", sep = "")

pattern
# [1] "^(866|867)"

filter(observations, rowSums(sapply(observations[-1], grepl, pattern = pattern)) != 0)

# A tibble: 2 × 4
#  patient  var1  var2  var3
#    <chr> <chr> <chr> <chr>
#1       a  8661  8651  2430
#2       b   865  8674  3456
filter(observations, Reduce("|", lapply(observations[-1], grepl, pattern = pattern)))

# A tibble: 2 × 4
#  patient  var1  var2  var3
#    <chr> <chr> <chr> <chr>
#1       a  8661  8651  2430
#2       b   865  8674  3456
dx<-c("866","867", "9089")
pattern = paste("^(", paste0(dx, collapse = "|"), ")", sep = "")

pattern
# [1] "^(866|867|9089)"

filter(observations, Reduce("|", lapply(observations[-1], grepl, pattern = pattern)))

# A tibble: 3 × 4
#  patient  var1  var2  var3
#    <chr> <chr> <chr> <chr>
#1       a  8661  8651  2430
#2       b   865  8674  3456
#3       c  8651  2866  9089
How can start a process and stop the process if "error" string appear in the console output strings in one lin

How can start a process and stop the process if "error" string appear in the console output strings in one lin


By : Jens Hodne
Date : March 29 2020, 07:55 AM
wish of those help If the goal is to exit ffmpeg if an error is thrown then add -xerror to your ffmpeg command, which will cause ffmpeg to exit upon error.
Query to find active records on a given date in a table recording "start" and "stop" dates

Query to find active records on a given date in a table recording "start" and "stop" dates


By : Adrian Palomera
Date : March 29 2020, 07:55 AM
help you fix your problem I have a list of "start / stop" activity logged in a table, each one associated with a date. I need to determine which users had "started" on a particular date - i.e. were in progress with the task. My current setup and query can be represented by this simplistic view of it: , Does this help?
code :
SELECT a.status_id
     , a.status_user_id 
     , a.status_date start
     , MIN(b.status_date) stop
  FROM registration_statuses a
  LEFT
  JOIN registration_statuses b
    ON b.status_user_id = a.status_user_id
   AND b.status_id > a.status_id
   AND b.status_activity = 'stop'
 WHERE a.status_activity = 'start'
 GROUP 
    BY a.status_id;

+-----------+----------------+------------+------------+
| status_id | status_user_id | start      | stop       |
+-----------+----------------+------------+------------+
|         1 |              1 | 2020-01-01 | 2020-01-19 |
|         2 |              2 | 2020-01-02 | 2020-01-31 |
|         4 |              1 | 2020-01-25 | 2020-01-31 |
+-----------+----------------+------------+------------+
Filtering rows based on "complex" strings in a column R/dplyr

Filtering rows based on "complex" strings in a column R/dplyr


By : Márcia Baptista
Date : March 29 2020, 07:55 AM
it should still fix some issue I am able to filter my dataset using the strings in a particular column, here's a sample dataset and how I did it.
code :
ID = c(1, 2, 3, 4)
String = c("Y N No", "Y", "Y No", "Y N")
df = data.frame(ID, String)
df %>% filter(!grepl("(N\\d+|N\\s)", String))

Output: [Y] [Y No]
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