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php mysql looking how to check if there are no result


php mysql looking how to check if there are no result

By : user2173503
Date : October 20 2020, 08:10 PM
will help you When using an aggregate function like max() you will always get a row, if there isn't a matching row it will return null.
So you need to change your test to...
code :
if($row['max_ricevuta'] != null){
    echo $row['max_ricevuta'];
}
else {
    echo "1";
}
$contabilita="d";


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check checkboxes from mysql result

check checkboxes from mysql result


By : user2674561
Date : March 29 2020, 07:55 AM
I wish this help you mysql_fetch_array() fetches one row from the result. Each row will contain one typeID. You will have to loop through the rows and do something. The code below will add all ID's to an array that you can search in.
code :
$typeIdArray = array();

while($row = mysql_fetch_array($query)) {
    $typeIdArray[] = $row['typeID'];
}
php, check if a result is in second column of mysql result

php, check if a result is in second column of mysql result


By : Qaz
Date : March 29 2020, 07:55 AM
this one helps. Hi i think you want to check that column c of any row has value 27 or not in fetching result PHP..then
1.If you can add condition column_c = 27 then use mysql_num_rows for count number of rows in result
code :
   $result = mysql_query("select * from table where column_b = ".$variable." AND column_c = 27") or die(mysql_error());

 if($result){
   if(mysql_num_rows($result) > 0){
     echo "true";
   }else{
     echo "false";
  }
 }
 $result = mysql_query("select * from table where column_b = ".$variable."") or die(mysql_error());

 $exist = "false";

 if($result){
   while($row = mysql_fetch_array($result)){
      if($row['column_c'] == 27){
        $exist = "true";
      }
   }
 }
 echo $exit;
MySQL, check if result has value, if not take another

MySQL, check if result has value, if not take another


By : Eugenia Larchenko
Date : March 29 2020, 07:55 AM
should help you out I have a table structure like this:
code :
SELECT a.Type, a.Page_ID
FROM   table a
         INNER JOIN
       (SELECT    Type, MAX(User_ID) AS User_ID
        FROM      table
        GROUP BY  Type ) b
       ON a.Type = b.Type AND a.User_ID = b.User_ID
Check if MySQL result is empty

Check if MySQL result is empty


By : Manjunath R S
Date : March 29 2020, 07:55 AM
Hope that helps I want to check if a MySQL result is empty and echo an error message. , Put it outside the loop:
code :
<?php
$ausgabe = "";
$sql = new rex_sql;

$sql->debugsql = 0; //Ausgabe Query

$sql->setQuery("SELECT * FROM $db_downloads WHERE gruppe = $gruppe_teilnehmer ORDER BY id DESC limit 4");

for($i=0;$i<$sql->getRows();$i++)
{

    $id = $sql->getValue("id");
    $dateiname = $sql->getValue("dateiname");
    $dateigroesse = $sql->getValue("dateigroesse");
    $dateipfad = $sql->getValue("dateipfad");
    $dateidatum = date("d.m.Y",strtotime($sql->getValue("dateidatum")));
    $dateizeit = date("H.i",strtotime($sql->getValue("dateidatum")));
    $download_teilnehmer = $sql->getValue("teilnehmer");
    $datei_projektnummer = $sql->getValue("projektnummer");
    $projektseite = $sql->getValue("projektseite");

    $ausgabe .= '<li><a href="index.php?article_id='.$projektseite.'"></a><i class="fa fa-file-o"></i>'.$dateiname.'<ul><li><i class="fa fa-calendar"></i>'.$dateidatum.' | '.$dateizeit.'</li><li><i class="fa fa-circle"></i>'.$datei_projektnummer.'</li></ul></li>';

    $sql->next();
}
if(empty($ausgabe)) {
    echo ("Error! No result!");
}
?>
How to check SQL(mysql ) result. PHP

How to check SQL(mysql ) result. PHP


By : Mayedul Islam
Date : March 29 2020, 07:55 AM
I wish this help you fetch result into an array and count items using count function, like this:
code :
$Name=$_COOKIE['PName'];
$sql = "select sysnum from hpc where handler='".$Name."' and stat='N';";
$sel = $conn->query($sql)->fetchall();
if(count($sel) > 0){       
 mycode;
}
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