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Drop first element of list of lists, condense list of lists? Too many elements?


Drop first element of list of lists, condense list of lists? Too many elements?

By : DoomsDayDave
Date : October 19 2020, 08:10 AM
this will help The object shown in the question is not a list of lists of 4 data frames each so if we call that object L then to get what is described we need to create LL like this. Now using LL we can compute the 3 items requested.
code :
LL <- list(L[1:4], L[5:8])

res1 <- sapply(LL, function(x) nrow(x$Comm))
res2 <- lapply(LL, function(x) x[names(x) != "Comm"])
res3 <- lapply(LL, function(x) do.call("rbind", x[names(x) != "Comm"]))


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Convert list of strings into list of lists with each element in list of lists as each iterable letter in string. All in

Convert list of strings into list of lists with each element in list of lists as each iterable letter in string. All in


By : rouraito
Date : March 29 2020, 07:55 AM
wish of those help With list of strings x: , With list and simple list comprehension:
code :
>>> x = ['foo', 'bar']
>>> y = [list(word) for word in x]
>>> y
[['f', 'o', 'o'], ['b', 'a', 'r']]
>>> y = map(list, x)
>>> y
[['f', 'o', 'o'], ['b', 'a', 'r']]
In python, trying to combine elements from a list of lists into a new list of combined-element lists

In python, trying to combine elements from a list of lists into a new list of combined-element lists


By : Claudiu
Date : March 29 2020, 07:55 AM
seems to work fine I am a python newbie.
code :
result = map(list, zip(*test))
Assigning element of list of lists by index sets all first elements of the lists

Assigning element of list of lists by index sets all first elements of the lists


By : Cesar Mu
Date : March 29 2020, 07:55 AM
may help you . When you do this v=[[0.0,0.0,0.0]]*12 you are getting a list with 12 references to the same list, to fix that use a comprehension instead:
code :
v = [[0.0,0.0,0.0] for _ in range(12)]
Python - Summing elements on list of lists based on first element of inner lists

Python - Summing elements on list of lists based on first element of inner lists


By : MarwanMR1
Date : March 29 2020, 07:55 AM
may help you . Accumulate with a defaultdict:
code :
>>> from collections import defaultdict
>>> data = defaultdict(int)
>>> L = [[0.5, 2], [0.5, 5], [2, 3], [2, 6], [2, 0.6], [7, 1]]
>>> for k, v in L:
...     data[k] += v
...     
>>> [[k,v] for (k,v) in data.items()]
[[0.5, 7], [2, 9.6], [7, 1]]
Is there any easy way to add elements in lists in a list to make all lists in a list has a same number of element?

Is there any easy way to add elements in lists in a list to make all lists in a list has a same number of element?


By : user2606562
Date : March 29 2020, 07:55 AM
Hope this helps Honestly, I didn't find out for this question cuz... I don't know how to search or google it. So it might be the basic problem, but if anyone can helps me, I would really appreciate it. , Using zip with itertools.zip_longest:
code :
import itertools

list(zip(*itertools.zip_longest(*results, fillvalue='')))
[(1, 2, 3, '', '', '', '', ''),
 (1, 2, 3, 4, '', '', '', ''),
 (1, 2, 3, 4, 5, 6, 7, 8)]
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