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Insert zero values for unexisting groups in Redshift

By : Gui Wege
Date : October 18 2020, 08:10 PM
will be helpful for those in need Use a cross join to generate the rows and then a left join to bring in the data:
code :
SELECT EXTRACT(year FROM created_at) AS year,
       EXTRACT(month FROM created_at) AS month,
       COUNT(t.member_id) as pageviews
FROM (SELECT DISTINCT EXTRACT(year FROM created_at) AS year, EXTRACT(month FROM created_at) AS month FROM TABLE) ym CROSS JOIN
     TABLE t
     ON EXTRACT(year FROM created_at) AS month = ym.year AND
        EXTRACT(month FROM created_at) AS month = ym.month AND
        t.member_id = m.member_id
GROUP BY ym.year, ym.month, m.member_id
ORDER BY ym.year, ym.month, m.member_id;

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Select unexisting values

By : karateboy
Date : March 29 2020, 07:55 AM
I wish this help you You can use a LEFT JOIN with a GROUP BY to do one query against the database and get the complete result;
code :
SELECT Tag, COUNT(ImgId) selected
  ON tags.TagId = TAGGED.TagId

Table insert unexisting values

By : user3924120
Date : March 29 2020, 07:55 AM
To fix the issue you can do Current situation tblGamePoints , Using a not exists condition seems easier to me:
code :
INSERT INTO tblGamePoints (Gamenumber, PlayerId, Game, Points) 
SELECT      3, tblPlayer.Id, 'FPS', 0 
FROM        tblPlayer 
WHERE       Game = 'FPS' AND 
            ValidatedEntry='1' AND 
            NOT EXISTS (SELECT *
                        FROM   tblGamePoints
                        WHERE  PlayerId = tblPlayer.Id AND Game = 3)

How to insert NULL values from Spark into Redshift?

By : Zade Zaman
Date : March 29 2020, 07:55 AM
like below fixes the issue You can specify the value in your COPY statement with NULL AS 'NULL' http://docs.aws.amazon.com/redshift/latest/dg/copy-parameters-data-conversion.html#copy-null-as
I would suggest trying out the spark-reshift library for loading Redshift. It takes care of a lot of these issues for you. https://github.com/databricks/spark-redshift

Calc aggregates across continuous groups of values in Redshift

By : user3725918
Date : March 29 2020, 07:55 AM
Does that help This is a so-called gaps-and-islands approach. Written on my phone so untested. But you should be able to search SO for that key-phrase.
code :
  sorted AS
      OVER (
        PARTITION BY userid
            ORDER BY start
        AS row_userid_start,
      OVER (
        PARTITION BY userid, status
            ORDER BY start
        AS row_userid_status_start
  MIN(start)   AS start,
  MAX(end)     AS end
  row_userid_status_start - row_userid_start

Redshift insert values into table

By : alista24ftp
Date : March 29 2020, 07:55 AM
With these it helps I'm not familiar with pg8000 so take this with a grain of salt.
The final query you want to run should end up looking like:
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