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Verilog : A task with continuous assign output for local variables

By : user2174259
Date : October 18 2020, 08:10 PM
help you fix your problem In Verilog, input arguments to a task are copied by value upon entry to the task, and output arguments get copied upon exit to the task. Nothing gets transferred through the arguments while the task consumes time. SystemVerilog adds a ref argument direction which means the argument gets passed as a reference. That allows activity with the argument to be seen while the task is active:
code :
task test(input [7:0] input_task, ref logic [7:0] output_task);

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How to 'assign' a value to an output reg in Verilog?

By : user1591205
Date : March 29 2020, 07:55 AM
Any of those help The assign statement is used for driving wires.
If you've somethings declared as a reg, then you have to give it values inside a procedure ( always or initial blocks ). It's best practice to only set values of regs in the same always block. eg:
code :
always @( * ) begin // combo logic block
   if( some_condition ) begin
      icache_ram_rw = 1'b0;
   end else begin
      icache_ram_rw = something_else;
// some parameter definitions to make logic 'read' clearer.
localparam READ = 1'b0; 
localparam WRITE = 1'b1;

// standard clocked logic 'template' that synthesis tools recognise.
always @( posedge clk or negedge resetb )
  if( !resetb ) begin  // asynchronous active low reset
     icache_ram_rw <= READ;
  end else if( some_enable_condition ) begin
     icache_ram_rw <= WRITE;
  end else begin
     icache_ram_rw <= READ;

How to assign a register to an output in verilog?

By : Dinesh
Date : March 29 2020, 07:55 AM
like below fixes the issue I'm having difficulty figuring out how to assign the value of temp to the out. I searched the web for an answer and tried all kinds of things but still cannot get the output assigned. Here's the code: , You probably meant to write
code :
module Reg8bit(
    input CLK,
    input En,
    input CLR,
    input [7:0] in,
    output reg [7:0] out // out is a variable, not a wire

    always @(posedge CLK)
        if (En)
            if (CLR)
                out <= 8'b0000_0000; // use Non-blocking assignments
                out <= in;

Modules in Verilog: output reg vs assign reg to wire output

By : Omar El-Said
Date : March 29 2020, 07:55 AM
This might help you Let's say module_a has register_a in it, which needs to be linked to module_b. Should register_a be declared separately and assigned to an output of module_a: , I think you are asking about the difference between the following:
code :
module my_dff (output reg q, input clk, d); //None Blocking style
  always @(posedge clk) begin
    q <= d;
module my_dff (output q, input clk, d);
  reg reg_q;
  assign q = reg_q; // Blocking style
  always @(posedge clk) begin
    reg_q <= d;
module fifo(output out, input clk, in);
  wire q0;
  reg q1;
  my_dff dff0 ( q0, clk, in );
  always @(posedge clk) begin
    q1 <= q0;
  my_dff dff1 ( out, clk, q1 );

How to assign inconstant value to reg in Task , In Verilog?

By : Zulaiha Dobia Abdull
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I have faced this Error. Although I seek whole the net, I did not find good answer. , The error message is quite self-explanatory. When you have
code :
reg isDR_Zero=(DR==10'b0000000000)?1'b1:1'b0;
  task Registers_Inc_Generator(output PC_inc,DR_inc,AC_inc, input [7:0]D,T, input[5:0]B, input[9:0] AC,DR, input R,Z);
      reg isDR_Zero;
      reg isAC_Zero;

I cannot assign output to value in Verilog

By : Mao
Date : March 29 2020, 07:55 AM
hop of those help? Your controlUnit doesn't seem to have any logic attached to memAddr, but memAddr is still an output of controlUnit. At the top level, you port map ADDR to .memAddr, and you also assign ADDR = pcOut. You're trying to drive ADDR in two different locations.
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