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how to conditionally change array values


By : user2174312
Date : October 18 2020, 08:10 AM
To fix this issue You could use np.cumsum on the product of a mask in the first column with the second column to get the cumulative sum and then numpy.stack to join the arrays:
code :
import numpy as np

a = np.array([[1, 2],
              [-1, 4],
              [1, 6],
              [-1, 8]])

mask = a[:, 0] == 1
third = np.cumsum(a[:, 1] * mask).reshape(-1, 1)

mask = a[:, 0] == -1
fourth = np.cumsum(a[:, 1] * mask).reshape(-1, 1)

result = np.hstack((a, third, fourth))

print(result)
[[ 1  2  2  0]
 [-1  4  2  4]
 [ 1  6  8  4]
 [-1  8  8 12]]


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How I can i conditionally change the values in a numpy array taking into account nan numbers?


By : Salim Ben Hssan
Date : March 29 2020, 07:55 AM
should help you out The fact that you have np.nan in your array should not matter. Just use fancy indexing:
code :
x[x>0] = new_value_for_pos
x[x<0] = new_value_for_neg
x[np.isnan(x)] = something_not_nan

How to conditionally change values of a column in R?


By : delfsdev
Date : March 29 2020, 07:55 AM
this will help
code :
df$class <- as.character(df$class)
df$class[df$class == "c"] <- ifelse(
  df$long[df$class=="c"] > (-75),
  "c(west)",
  "c(east)"
)
##

How can I change DF values conditionally with value from another column


By : darren
Date : March 29 2020, 07:55 AM
wish of those help As we are changing only the column values from 6:10, just loop over those and replace it with the 4th column value
code :
df[6:10] <- lapply(df[6:10], function(x) ifelse(x == "0/0", df[[4]], x))
i1 <- df[6:10] == "0/0"
df[6:10][i1]  <- df$V4[row(df[6:10])][i1]
for(i in names(df)[6:10]) {
    df[,i] <- ifelse(df[,i] == "0/0", df[[4]], df[,i])
 }
df
#     V1    V2 V3 V4 V5  V6 V7  V8  V9 V10
#1 chr1A 63248  .  A  G   A  A   A ./.   A
#2 chr1A 80950  .  A  C 1/1  A ./.   A   A
#3 chr1A 81080  .  C  G   C  C   C ./.   C
#4 chr1A 81084  .  C  T 0/1  C   C ./.   C

Conditionally Change Icons for Array Values


By : Daniel
Date : March 29 2020, 07:55 AM
it helps some times Here is my simple code to call and display my posts , During post.map, you can try something like this:
code :
const ICONS = {
  A: "icon-a",
  B: "icon-b",
  C: "icon-c",
  D: "icon-d"
};

// Displays data from API call successfully //
{
  this.state.posts.map(post => {
    return (
      <View key={post.id}>
        <Text>
          {post.category},{post.content}
        </Text>
        <Icon type={ICONS[post.category]} />
      </View>
    );
  });
}

Conditionally change the values of a Series based on the values of other columns


By : TheChovix
Date : March 29 2020, 07:55 AM
like below fixes the issue I'm experiencing/learning Python with a DataFrame having the following structure: , You forgot to return the value in your function.
code :
def myfunc(left_side, right_side, value):
    if (left_side == "") | (right_side == ""):
        return np.nan
    elif left_side != right_side:
        return 0
    else:
        return value
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