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Iterate through list and print 'true' if list element is of a certain type

By : Jeroen
Date : October 18 2020, 08:10 AM
wish of those help You can do this using isinstance:
code :
for i in listt:
    if isinstance(i,str):
for i in listt:
    if type(i) is str:

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How do I iterate through a list to print each variable in the list?

By : Avatron Software
Date : March 29 2020, 07:55 AM
it fixes the issue If i have this as my code: , From your description, I think you want something like this:
code :
>>> a = 1
>>> b = 2
>>> c = [3, 4, 5]
>>> d = [6, 7, 8]
>>> for cx, dx in zip(c, d):
        for item in (a, b, cx, dx):


How to write a for-loop to iterate through the list and print the data of every other element of the list

By : mohamed amine
Date : March 29 2020, 07:55 AM
Hope this helps Assuming each Node has a data member and a pointer/reference to the next node, you can do a while loop like you would normally do, but only output on odd or even iterations, so your code could look something like:
code :
for(Node* myList = head, int i = 0; myList != nullptr; myList = myList->next, ++i)
    if(i % 2) == 0)
        std::cout << myList->data << std::endl;

Pandas - iterate through dataframe and join if any element of a list matches any element of another list

By : user1844852
Date : March 29 2020, 07:55 AM
wish of those help I would use list comprehension once you have object dtypes in your series, and pandas string methods and iterative methods are very slow.
code :
elements = [(item, elem) for item in series_a.tolist()\
                         for elem in series_b.tolist()\
            if bool(set(item).intersection(elem))]

df_final = pd.DataFrame(elements)

The most correct way to iterate over a list in haskell, and return the element for which a condition is true

By : hong Wang
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I have a function which takes some argument and calls another function which returns a list of the form [a_1, a_2, ..., a_n]. , How about if you define
code :
satisfies:: [t]-> (t -> Bool) -> Maybe t
satisfies [] _ = Nothing
satisfies (x:xs) p = case p x of
    True -> Just x
    False -> satisfies xs p

Iterate list(a) through a bigger list(b) to give True/False values if items in list(a) exist in list(b)

By : Ambreka Perry
Date : March 29 2020, 07:55 AM
I hope this helps you . I have two lists:
code :
a = ['A', 'B', 'C', 'D'] 
b = ['B', 'C', 'D', 'E', 'F', 'G', 'H', 'I']
c = [x in b for x in a]
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