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Rails 5 scope like multiple partial strings


By : user2174388
Date : October 18 2020, 08:10 AM
this one helps. PostgreSQL allows you to apply a boolean valued operator to an entire array of values using the op any(array_expr) construct:
code :
expression operator ANY (array expression)
expression operator SOME (array expression)
array[value, value, ...]
scope :by_templates, ->(templates) { joins(:template).where('templates.label ~* any(array[?])', templates) }
# Yes, this class method is still a scope.
def self.by_templates(templates)
  joins(:template).where('upper(templates.label) = any(array[?])', templates.map(&:upcase) }
end


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Ruby on Rails - Scope of Instance Variables with Partial Views


By : Damon Black
Date : March 29 2020, 07:55 AM
around this issue When you do a redirect, the browser sends an entirely new request, so all of the data from the previous request is inaccessible. You probably don't want to be doing a redirect here; no amount of scope will help you when you're looking at separate runs through your controller.
Think about your design a little bit - what are you trying to do? If the selection is something sticky, maybe it should go in the session. If the change is only in a partial, maybe you should use an Ajax call. Maybe the solution is as simple as rendering the index template instead of redirecting to the index action.

Does dictionary contain key containing multiple partial strings?


By : styme11
Date : March 29 2020, 07:55 AM
will be helpful for those in need This way is less verbose, has the opportunity to break the search early when matching keys are found, but still makes two complete passes over the keys in the worst case.
code :
if any('L_' in key for key in dict) and any('R_' in key for key in dict):
    print 'has both'
if any('L_' in key and 'R_' in key for key in dict):
    print 'has both'
RS=False
LS=False
for each in dict:
    if "L_" in each:
        LS=True
    if "R_" in dict:
        RS=True
    if LS and RS:
        print 'has both'
        break

R filter rows based on multiple partial strings applied to multiple columns


By : Hassoun Khelil
Date : March 29 2020, 07:55 AM
To fix this issue Sample of dataset: , Perhaps we need
code :
df %>%
   filter_all(any_vars(grepl(pattern="^(E11|E16|E86|E87|E88)", .)))
library(dplyr)
library(purrr)
df %>%
   map(~grepl(pattern="^E11|^E16|^E86|^E87|^E88", .)) %>% 
   reduce(`|`) %>%
   df[.,]

Filter a list that contain ALL of multiple partial strings in R


By : baytown43
Date : March 29 2020, 07:55 AM
may help you . I am trying to filter a list of file names, based on a set of keywords the user picked in a shiny app, and the final list should be only files that contain ALL partial keywords
code :
filenames[Reduce("&", lapply(keywords, function(x) grepl(x, filenames)))]
#[1] "AdditionalListMode_M1bI Syn 60 90 90 110 2017-06-20 13u20.csv"
#[2] "AdditionalListMode_M1bI Syn 60 90 90 110 2017-06-21 13u21.csv"

How to filter a pandas dataframe using multiple partial strings?


By : Hello
Date : March 29 2020, 07:55 AM
this will help Use str.contains with | for multiple search elements:
code :
mask = df['Answers'].str.contains(regex_pattern)
final_df = df[mask]
strings_to_find = ["not in","not on","not have"]
regex_pattern = '|'.join(strings_to_find)
regex_pattern 
'not in|not on|not have'
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