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Oracle VIEW - Convert VARCHAR2 to DATE and find MIN/MAX of DATE

Date : October 17 2020, 08:10 PM
around this issue Data: , You can try this one:
code :
 min(to_char(to_date(begin_dt, 'MMDDYYYY'), 'MM/DD/YYYY'))
to_char(min(to_date(begin_dt, 'MMDDYYYY')), 'MM/DD/YYYY')

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Convert multiple date varchar2 to date format in Oracle 11g

By : Ross Epstein
Date : March 29 2020, 07:55 AM
wish helps you I'd suggest using a case statement with regexp_like conditions to detect likely formats and return dates using the appropriate date mask in the then clauses e.g.:
code :
with tz as (
SELECT distinct tzabbrev
     , first_value(min(tzname)) over (partition by tzabbrev order by count(*) desc) tzname
  FROM v$timezone_names 
 group by tzabbrev
     , TZ_OFFSET(tzname)
), dta as (
select yt.install_date
     , regexp_replace(yt.install_date,tzabbrev,tzname,1,1,'i') install_date2
  from your_table yt
  left join tz
    on regexp_like(install_date, tz.TZABBREV,'i')
select install_date, install_date2
     , to_timestamp_tz( install_date2
              , case 
                  when regexp_like(install_date2,'^[A-Z]{3,} [A-Z]{3,} [0-9]{1,2} [0-9]{1,2}(:[0-9]{2}){1,2} [[:print:]]{5,} [0-9]{2,4}','i') then 'DY MON DD HH24:MI:SS TZR YYYY'
                  when regexp_like(install_date2,'^[A-Z]{4,},? [A-Z]{3,},? [0-9]{1,2},? [0-9]{2,4}','i') then 'DAY MONTH DD YYYY'
                  when regexp_like(install_date2,'^[A-Z]{3},? [A-Z]{3,},? [0-9]{1,2},? [0-9]{2,4}','i') then 'DY MONTH DD YYYY'
                  when regexp_like(install_date2,'^[0-9]{1,2}[-/][0-9]{1,2}[-/]([0-9]{2}){1,2}') then 'MM-DD-RRRR'
                  when regexp_like(install_date2,'^[0-9]{1,2}[-/ ][A-Z]{3,}[-/ ]([0-9]{2}){1,2}','i') then 'DD-MON-RRRR'
                  when regexp_like(install_date2,'^[A-Z]{3,}[-/ ][0-9]{1,2},?[-/ ]([0-9]{2}){1,2}','i') then 'MON-DD-RRRR'
                  when regexp_like(install_date2,'^(19|20)[0-9]{6}') then 'RRRRMMDD'
                  when regexp_like(install_date2,'^[23][0-9]{5}') then 'DDMMRR'
                  when regexp_like(install_date2,'^[0-9]{6}') then 'MMDDRR'
                  when regexp_like(install_date2,'^[01][0-9]{7}') then 'MMDDRRRR'
                  when regexp_like(install_date2,'^[23][0-9]{7}') then 'DDMMRRRR'
                  ELSE NULL
                  when regexp_like(install_date2, '[0-9]{1,2}(:[0-9]{2}){1,2}$') then ' HH24:MI:SS'
                  when regexp_like(install_date2, '[0-9]{1,2}(:[0-9]{2}){1,2} ?(am|pm)$','i') then ' HH:MI:SS AM'
                  else null
  from dta;

Convert Oracle VARCHAR2 to DATE and exclude invalid data

By : Shawn Fang
Date : March 29 2020, 07:55 AM
Hope that helps I have column column_name VARCHAR2 with various data. To convert it to DATE datatype I wrote following expression: , You could write a function like this:
code :
SELECT varchar_to_date(column_name) FROM schema.table;

convert VARCHAR2 data to date in oracle

By : Georges Abou Haydar
Date : March 29 2020, 07:55 AM
I hope this helps you . I have the following data in TIMESTAMP column , One method uses to_date():
code :
where to_date(timestamp, 'YYYY-MM-DD HH24:MI:SS.F') >= date '2018-01-04' and
      to_date(timestamp, 'YYYY-MM-DD HH24:MI:SS.F') < date '2018-01-09'
where timestamp >= '2018-01-04' and
      timestamp  < '2018-01-09'

Oracle SQL - convert a varchar2 into a date

By : Taisei
Date : March 29 2020, 07:55 AM
Any of those help
"The Database contains another column with the correct date for each time"
code :
select to_date(qdate||qtime, 'yyyymmddhh24miss') as qdatetime
       , to_date(zdate||ztime, 'yyyymmddhh24miss') as zdatetime
from your_table
select id
       , zdatetime - qdatetime as time_diff
from (  select id
               , to_date(qdate||qtime, 'yyyymmddhh24miss') as qdatetime
               , to_date(zdate||ztime, 'yyyymmddhh24miss') as zdatetime
      from your_table
, extract( hour from (zdatetime - qdatetime) day to second) as hrs_ela

Convert varchar2 string to date - Oracle SQL Developer

By : yeram
Date : March 29 2020, 07:55 AM
will help you Need to covert VARCHAR2 string in format of 20150101, 20150102, 20150125.....etc into date in format of 01/01/2015, 01/02/2015.... etc. , Just use to_date() that is what it is there for:
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