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Python print function does not return the updated variable

By : Nicki
Date : October 17 2020, 08:10 AM
like below fixes the issue Everything on the right-hand side is evaluated first. You can use the python byte-code dissasembler to see what is happening:
code :
>>> import dis
>>> dis.dis('x, y = x + 2, print(x)')
  1           0 LOAD_NAME                0 (x)
              2 LOAD_CONST               0 (2)
              4 BINARY_ADD
              6 LOAD_NAME                1 (print)
              8 LOAD_NAME                0 (x)
             10 CALL_FUNCTION            1
             12 ROT_TWO
             14 STORE_NAME               0 (x)
             16 STORE_NAME               2 (y)
             18 LOAD_CONST               1 (None)
             20 RETURN_VALUE
temp = (x + 2, print(x))
x, y = temp
>>> dis.dis('foo, bar, baz, bang  = bang, baz, bar, foo')
  1           0 LOAD_NAME                0 (bang)
              2 LOAD_NAME                1 (baz)
              4 LOAD_NAME                2 (bar)
              6 LOAD_NAME                3 (foo)
              8 BUILD_TUPLE              4
             10 UNPACK_SEQUENCE          4
             12 STORE_NAME               3 (foo)
             14 STORE_NAME               2 (bar)
             16 STORE_NAME               1 (baz)
             18 STORE_NAME               0 (bang)
             20 LOAD_CONST               0 (None)
             22 RETURN_VALUE
x, y = y, x
x = y
y = x

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Python why variable and return show difference value from print variable?

By : Sundar Raja94
Date : March 29 2020, 07:55 AM
Any of those help One is the repr() representation of the string, the other the printed string. The representation you can paste back into the interpreter to make the same string again.
The Python interactive prompt always uses repr() when echoing variables, print always uses the str() string representation.
code :
>>> "'\\x04\\x00\\x00\\x00\\x00\\x00\\x00\\x00g\\xc4|\\x00\\x00\\x00\\x00\\x00'"
>>> print "'\\x04\\x00\\x00\\x00\\x00\\x00\\x00\\x00g\\xc4|\\x00\\x00\\x00\\x00\\x00'"
>>> print repr("'\\x04\\x00\\x00\\x00\\x00\\x00\\x00\\x00g\\xc4|\\x00\\x00\\x00\\x00\\x00'")

User defined PHP function fails to return updated variable

By : s.roga
Date : March 29 2020, 07:55 AM
seems to work fine I am having some difficulty finding anything quite similar to what I am trying to accomplish with my code. I have a while loop that executes for each instance of a variable located in a mysql database. , try changing
function postcode($partnum,$lqty)

python can't return a variable but can print

By : user2460757
Date : March 29 2020, 07:55 AM
This might help you You are doing recursive calls to subset_sum, but you are not passing the returned value from the subcall to the caller.
If you add a return statement in the loop for recursive calls, you get what you are searching for, if the subcall found something.
code :
def findFourPlus(itemCount, seq, goal):
    goalDifference = float("inf")
    closestPartial = []
    hello = subset_sum(itemCount, seq, goal, 0, closestPartial, partial=[])
    return hello #doesn't return value from subset_sum()

def subset_sum(itemCount, seq, goal, goalDifference, closestPartial, partial):
    s = sum(partial)

    # check if the partial sum is equals to target
    if(len(partial) == itemCount):
        if s == goal:
                print("FOUND YAA")
                return partial #right now doesn't return anything. I intend for it to break out of this function as soon as it finds one pair of solution. 

            if( abs(goal - s) <= goalDifference):
                #print(abs(goal-s), goalDifference, closestPartial)
                goalDifference = abs(goal - s)
                closestPartial[:] = partial
                #print(abs(goal-s), goalDifference, closestPartial)
                return closestPartial

    for i in range(len(seq)):
        n = seq[i]
        remaining = seq[i+1:]
        t = subset_sum(itemCount, remaining, goal, goalDifference, closestPartial, partial + [n])
        print t
        if t:
            return t

a = findFourPlus(2, [1,2,3,4,5], 6)
print "a=", a
[1, 5]
[1, 5]
a= [1, 5]

python, functions in general: return string and print function OR just print statement in function?

By : JEONG WooHo
Date : March 29 2020, 07:55 AM
With these it helps Definitely have the function return the string and print as late as possible!
Printing early would violate the open-closed principle. That is, in general your code should strive to be closed to modification. This ensures that if you decide, later, that you want to print the string output twice, or pass the string output to an API, or save the string output in a file, you don't have to modify the original code which puts together the string (the book.show_cache function)
code :
def print_cache():
  print book.show_cache()

def save_cache_to_file():

def search_google_for_cache():
  // google.search(book.show_cache())
def print_cache():
  vocab = ['hola', 'como', 'estas', 'bien', 'y', 'tu']
  // more code?
  print vocab

def save_cache_to_file():
  vocab = ['hola', 'como', 'estas', 'bien', 'y', 'tu']
  // more code?

def search_google_for_cache():
  vocab = ['hola', 'como', 'estas', 'bien', 'y', 'tu']
  // more code?
  // google.search(vocab)

How can I print more than one variable in my print function(Python)?

By : Jan-Niklas
Date : March 29 2020, 07:55 AM
will help you I'm brand new to python and my teacher showed me an example on how to write multiple variables in a print function but I am getting a syntax error. Did I write it wrong? How can I fix this? , Use this code.
code :
def fahrenheit_to_celcius(num):
    print("When you convert %s to celcius the result is %s" % (num, 
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