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How to reuse a variable in shell script when used in curl?

By : Bill Sullivan
Date : October 17 2020, 08:10 AM
wish helps you When you are using a shell that supports arrays, you can avoid the need for a temporary configuration file.
code :
curl_opts=(-s -o /dev/null -w "%{http_code}")
if /* some condition */
  curl_opts+=(-H "Authorization: Bearer $JWT")
  curl_opts+=(--cert "$ADMIN_CERT_PATH" --key "$ADMIN_KEY_PATH")


response_code="$(curl "${curl_opts[@]}" "$status_url")"

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Shell script: output text after cURL variable

By : yka
Date : March 29 2020, 07:55 AM
like below fixes the issue I am trying to do something simple but it's not working. I am trying to echo a stock price from a variable and follow it with text. The problem is that the text does not follow the variable and goes in front of it. , The variable $stock has \r\n at its end.
code :
$ echo $stock | hexdump -c 
0000000   1   0   2   .   9   9  \r  \n                                
stock=$(curl -s 'http://download.finance.yahoo.com/d/quotes.csv?s=AAPL&f=l1'| tr -d '\r\n')

$ echo ".. $stock .."
.. 102.99 ..

Shell Script CURL JSON value to variable

By : user3582748
Date : March 29 2020, 07:55 AM
it should still fix some issue You could use perl module on command line:
1st, ensure they is installed, under debian based, you could
code :
sudo apt-get install libjson-xs-perl
cpan App::cpanminus
cpan JSON::XS
curlopts=(-X POST -H
    "Content: apent-type: application/x-www-form-urlencoded"
    -d username="$USERNAME" -d password="$PASSWORD")

. <(
    perl -MJSON::XS -e '
        $/=undef;my $a=JSON::XS::decode_json <> ;
        printf "declare -A Json=\047(%s)\047\n", join " ",map {
        } qw|queueToken success eta position|;
    ' < <(
        curl "${curlopts[@]}" $curlurl
echo ${Json[queueToken]}

echo ${Json[eta]}

How to assign string value to variable from curl and jq in shell script?

By : Vinton Jing
Date : March 29 2020, 07:55 AM
it helps some times I am trying to assign a string I get from curl and jq to a variable. this is my code below, but it doesn't work. I am a Mac user.
code :
$ value=$(curl -X GET https://apitest.onkore.com/onkore/api/v1/storeCategories | 
  jq '.[2] | ._id')
$ echo "$value"

Assign a variable in curl URL shell script

By : Music_lovers4
Date : March 29 2020, 07:55 AM
help you fix your problem I believe the problem is in the first headr -H flag. It has white space in the string which might be getting interpreted as another argument to curl.
Here I made some generic modification to the script. I don't have an environment to test it. Hope it helps.
code :
$ cat test.sh

h1flag="'X-Application-Authorization: Bearer Token'"
h2flag="'Accept: application/vnd.application.v2.1+xml'"
while read -r id
    curl --verbose -H "${h1flag}" -H "${h2flag}" -X "${reqflag}" "${baseurl}/$id" 
done < input.csv
$ curl --verbose \
  -H 'X-Application-Authorization: Bearer Token' \
  -H 'Accept: application/vnd.application.v2.1+xml' \
  -X DELETE https://api.application.com/hardwares/1945603

use curl in shell script to substitue a variable

By : amr
Date : March 29 2020, 07:55 AM
To fix this issue No variable substitution in single quotes. Switch to double around the expansion, like this:
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