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Python getting the grouped values from positive look ahead


By : RyanSchuton
Date : October 17 2020, 08:10 AM
it should still fix some issue Your first statement how to get the match objects from positive look ahead and later statements are a bit confusing. Assuming you want to capture index name FIRST_ONE and remaining column names, PLATFORM_CD ,SYSTEM_NAME ,DB_NAME ,TABLE_NAME ,COLUMN_NAME, you can simplify your regex and use this to capture all you need.
code :
(?:\w+)(?=\s*(?:\(|,|\)))
import re
line = 'PRIMARY INDEX FIRST_ONE ( PLATFORM_CD ,SYSTEM_NAME ,DB_NAME ,TABLE_NAME ,COLUMN_NAME );'
arr = re.findall(r'(?:\w+)(?=\s*(?:\(|,|\)))', line)
print(arr)
['FIRST_ONE', 'PLATFORM_CD', 'SYSTEM_NAME', 'DB_NAME', 'TABLE_NAME', 'COLUMN_NAME']


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Understanding Positive Look Ahead Assertion


By : mobappcode
Date : March 29 2020, 07:55 AM
like below fixes the issue Lookarounds are zero-width assertions. They don't consume any characters on the string.
To touch briefly on the bolded portions of the documentation:

JS - Positive Look Ahead & End Of Line


By : Dephei
Date : March 29 2020, 07:55 AM
will be helpful for those in need You need to understand how look-aheads work.
The (?=[cd])$ positive look-ahead checks if the following characters match the pattern that follows the look-ahead (in your case, the end of string). The end of string is not c nor d. Thus, there is no match.
code :
^[ab](?=[cd]$)

python regex look ahead positive + negative


By : Arun Gopi
Date : March 29 2020, 07:55 AM
this will help This regex will get 456. My question is why it CANNOT be 234 from 1-234-56 ? Does 56 qualify the (?!\d)) pattern since it is NOT a single digit. Where is the beginning point that (?!\d)) will look for? ,
My question is why it CANNOT be 234 from 1-234-56?
code :
rx = r'\d(?=(?:\d{3})+(?!\d))'

Regex positive look behind and look ahead


By : George Benoy
Date : March 29 2020, 07:55 AM
I wish this helpful for you No need to use lookbehind. You can use this regex and grab the captured group #1:
code :
^ABC\S+\s+(\S+)(?=.*\sactive\b)
import re
p = re.compile(ur'^ABC\S+\s+(\S+)(?=.*\sactive\b)', re.MULTILINE)

re.findall(p, input)

Python regex positive look ahead


By : Acoo C Johnzkie AE
Date : March 29 2020, 07:55 AM
this will help The difference is that the first lookahead expects exactly one whitespace character before the digit or capital letter while the second one expects at least one whitespace character but as many as possible.
The + is called a quantifier. It means 1 to n as many as possible.
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