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looping through 2 arrays


By : user2175050
Date : October 16 2020, 08:10 AM
wish help you to fix your issue You don't want a nested loop - you simply need to link the ith item in links to the ith item of hrefLinks. With forEach, you can do this just by using the second argument to the callback, which will refer to the current index being iterated over:
code :
const list = document.body.appendChild(document.createElement('ul'));


const links = ['Home', 'Contact', 'About'];
const hrefLinks = ['/', 'contact', 'about'];

links.forEach((linkName, i) => {
  const li = document.createElement('li');
  const a = document.createElement('a');
  a.href = hrefLinks[i];
  a.textContent = linkName;
  li.appendChild(a);
  li.className = 'nav-link';
  list.appendChild(li);
});


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Sending arrays of arrays as parameter and then again looping though each array


By : Carolino
Date : March 29 2020, 07:55 AM
will be helpful for those in need I don't know why you are trying to fetch same value multiple time. Your below code is running multiple time without any reason.
code :
vcount=Video.where(:users_notified=>f).count
icount=Image.where(:users_notified=>f).count
acount=Audio.where(:users_notified=>f).count

@count << vcount + icount + acount

vcat=###ALL VIDEO CATEGORIES
icat=###ALL IMAGE CATEGORIES
acat=###ALL AUDIO CATEGORIES

@cats << vcat + icat + acat
vcount=Video.where(:users_notified=>f).count
icount=Image.where(:users_notified=>f).count
acount=Audio.where(:users_notified=>f).count

@count << vcount + icount + acount

vcat=###ALL VIDEO CATEGORIES
icat=###ALL IMAGE CATEGORIES
acat=###ALL AUDIO CATEGORIES

@cats << vcat + icat + acat

User.signed_in_users.find_in_batches(:batch_size => 100 ) { |users| users.each { |user| 

###########now sending all these parameter to mailer(array of arrays)
  UserMailer.notify_user(user.email,@count,@cats)

} } ###loop ends

Looping through arrays in VBA


By : Tom Lai
Date : March 29 2020, 07:55 AM
it should still fix some issue By default Excel wants to place a 1-D array on the sheet in a row, not in a column, so you get the first element of the array in each cell when you try to put it in a column.
All values are zero becuase your 1-d array is zero-based and you didn't populate that slot in your loop.
code :
Sheet2.Range(Sheet2.Cells(1, 1), Sheet2.Cells(columns, 1)) = _
     Application.Transpose(Maxindex)

looping cell2mat to convert cell arrays to arrays


By : user5502307
Date : March 29 2020, 07:55 AM
may help you . You cannot assign a whole matrix(which is in a cell) to one index
lets take the following example
code :
>> cell_test ={[1 2 3;4 5 6],[1 2 3; 7 8 9]}

cell_test = 

    [2x3 double]    [2x3 double]
>> cell_test{1}

ans =

     1     2     3
     4     5     6

>> b(1) = cell_test{1}
Subscripted assignment dimension mismatch.
>> i = 1

i =

     1

eval(['B_',num2str(i)  ,'=cell_test{i}'])

B_1 =

     1     2     3
     4     5     6

PHP Arrays looping and creating multi dimensional arrays


By : user7149218
Date : March 29 2020, 07:55 AM
This might help you Maybe something like this? https://iconoun.com/demo/temp_tonywiz.php
code :
<?php // demo/temp_tonywiz.php
/**
 * Working with arrays
 *
 * https://stackoverflow.com/questions/45264342/php-arrays-looping-and-creating-multi-dimensional-arrays
 */
error_reporting(E_ALL);
echo '<pre>';


$qty = 120;
$arr = [ ['order' => 'order001', 'qty' => 90], ['order' => 'order002', 'qty' => 100] ];
$out = [];

foreach ($arr as $sub)
{
    if ($qty <= 0) break;
    if ($sub['qty'] <= $qty)
    {
        $out[] = $sub;
        $qty = $qty - $sub['qty'];
    }
    else
    {
        $sub['qty'] = $qty;
        $out[] = $sub;
    }
}
print_r($arr);
print_r($out);

Javascript looping through arrays of arrays


By : Adnan Iqbal
Date : March 29 2020, 07:55 AM
I wish did fix the issue. The variable allTop should be defined before the loop as an array, and returned after the loop ends:
code :
function largestOfFour(arr) {
  var allTop = [];
  
  for (var i = 0; i < arr.length; i++) {
    var top = arr[i].sort(function(a, b) {
      return b - a;
    });
    allTop.push(top[0]);
  }
  
  return allTop;
}

console.log(largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]));
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