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Solution to get individual value passed to each element


By : Randy Doank
Date : October 16 2020, 08:10 AM
hop of those help? You have to target the respective anchor element in each iteration. You can use jQuery's .eq() with the current value of i.
code :
var arr = [1, 2, 3, 4, 5];
var $a = $('a');
for(let i = 0; i < arr.length; i++) {
  $a.eq(i).attr('href', arr[i]);
  $a.eq(i).text('Link ' +arr[i]); // for test
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<a></a>
<a></a>
<a></a>
<a></a>
<a></a>
var arr = [1, 2, 3, 4, 5];
$('a').each(function(i){
  $(this).attr('href', arr[i]);
  $(this).text('Link ' +arr[i]); // for test
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<a></a>
<a></a>
<a></a>
<a></a>
<a></a>


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javascript variables for individual elements passed into individual animations


By : william
Date : March 29 2020, 07:55 AM
Does that help Try mine: http://jsfiddle.net/uTV5k/12/
Got it working
code :
$(function() {


    $('.home-mod').each(function() {
        var moduleLink = $(this).find('.mod-link').innerHeight();
        $(this).find('.mod-info').css("top", "-" + moduleLink + "px");
    });

    $("div.mod-info").hover(function() {

        var moduleInfo = $(this).height();


        $(this).animate({
            top: "-" + moduleInfo + "px"
        });

    }, function() {

        var moduleLink = $(this).find('.mod-link').innerHeight();

        $(this).animate({
            top: "-" + moduleLink + "px"
        });

    });

    $(".home-mod").click(function() {

        window.location = $(this).find("a.mod-link").attr("href");

        return false;
    });

});

How to convert calculator operation element to a string to get the solution and then return the solution back into the e


By : Alejandro Figueroa
Date : March 29 2020, 07:55 AM
like below fixes the issue So I'm making a JQuery calculator in codepen and I'm basically having the buttons write out the equation. So far so good. However I run into some problems once I try to get back the result of the calculations. How do I convert the calculations element in HTML into a variable string in JQuery and then return it back into the HTML as the solution? Here is my codepen project link, as well as the problematic section of code: http://codepen.io/Starkiller12/pen/eJYGXY , You can do like following:
code :
$("#equal").click(function() {
    var arr = $('p').text().split('+');
    var first=parseInt(arr[0]);
    var two=parseInt(arr[1]);
    $("p").empty();
    $("p").html(first + two);
  })

Massive MVC solution into individual solutions


By : asdasd
Date : March 29 2020, 07:55 AM
Hope that helps Turn your core projects into Nuget packages. This will give you both an easy way to add them to other projects in different solutions and seamless version management. You can host your own private Nuget repository, so making them public at the official Nuget site is not a requirement.
As for your views, use Razor Generator to compile them in your class library(ies) and access them in your other projects.

How to search for individual rows in multidimensional array then perform calculation for each individual element in cert


By : user2737186
Date : March 29 2020, 07:55 AM
should help you out Instead of repeating the entire cout statements in each if case, you could first determine an index which you can use in display code:
code :
int index = 0;

if (key >= 80000 && key < 90000)
    index = 0;
else if (key >= 90000 && key < 100000)
    index = 1;
else if (key >= 100000 && key < 110000)    
    index = 2;
else
    // You should do some check if an invalid key is provided

// Now display    
cout << "L/R_Ext = "     << (arr[index][1] + arr[index+1][1]) / 2 << endl;
cout << "L/R_ Outbrd = " << (arr[index][2] + arr[index+1][2]) / 2 << endl;
cout << "L1 R4 = "       << (arr[index][3] + arr[index+1][3]) / 2 << endl;
cout << "L2 R3 = "       << (arr[index][4] + arr[index+1][4]) / 2 << endl;
cout << "Forward = "     << (arr[index][5] + arr[index+1][5]) / 2 << endl;
cout << "Center = "      << (arr[index][6] + arr[index+1][6]) / 2 << endl;
cout << "Mid = "         << (arr[index][7] + arr[index+1][7]) / 2 << endl;
cout << "Aft = "         << (arr[index][8] + arr[index+1][8]) / 2 << endl;

How to chain individual elements of list into one individual element in Python


By : user3437331
Date : March 29 2020, 07:55 AM
Any of those help I have the following list , Use str.join:
code :
List1 = [''.join(List1)]
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