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How do I swap the first and second items in an array of strings?

By : user2175215
Date : October 15 2020, 08:10 PM
wish help you to fix your issue I have a list of coordinates in string format that has the longitude and the latitude respectively. I would like to have the latitude and THEN longitude: , Here's a more functional approach:
code :
let str = "POLYGON ((-97.7157864909859 30.406523563068, -97.7165355983688 30.4068866173208, -97.7167879301601 30.406495457696, -97.7168046574092 30.4065112735542, -97.7168203607564 30.406527859154, -97.7168349935064 30.4065451649171))"
let formattedString = str.replacingOccurrences(of: "POLYGON ((", with: "").replacingOccurrences(of: "))", with: "")

// split by commas, not spaces, because in the original string, pairs of 
// coordinates are separated by commas
let coordianates = formattedString.components(separatedBy: ", ")

// Here I transform each pair of coordinate into an array with two elements, 
// reverse it, and flatten the whole array
let flipped = coordianates.flatMap { $0.components(separatedBy: " ").reversed() }

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Swap two strings in an array, Java

By : james
Date : March 29 2020, 07:55 AM
will be helpful for those in need if(seats[i] == name1)// this is wrong
when you compare Strings you should use .equals or .EqualsIgnoreCase
code :
        temp1 = name1;
        temp2 = name2;
        name1 = temp2;
        name2 = temp1;  

//you can directly do this to swap
  //  temp = name1;
  //  name1 = name2;
  //  name2 = temp;


Swap two strings using array PHP

By : Laller
Date : March 29 2020, 07:55 AM
wish of those help Although a gotcha, this is expected behavior. You replaced all E with e, then all e with E. So the result is E and E.
You will need to do this in two passes, use a placeholder, or use strtr(). As commented by mario, the appropriate function to swap strings is strtr():
code :
$edited = strtr($original, $swap);

Typescript swap array Items

By : Kevin Eimer
Date : March 29 2020, 07:55 AM
wish helps you how to swap two elements using typescript , Why not use destructuring and an array.
code :
[elements[0], elements[3]] = [elements[3], elements[0]];

Vue.js swap array items

By : Restu
Date : March 29 2020, 07:55 AM
it should still fix some issue While @dfsq is correct about the use of index++ Vue doesn't recognize native mutations of arrays due to the inability to observe them. you have to use a mutation method to change them.
try this:
code :
.then(() => {
  let rows = [this.forums[index], this.forums[index + 1]];
  this.forums.splice(index, 2, rows[1], rows[0] );

Swap two characters in the cell array of strings

By : Saranya Thangaraj
Date : March 29 2020, 07:55 AM
Hope that helps I have a cell array of string and I want to swap A and B in a percentage of the cell array , like 20%, 30% of the total number of strings in the cell array For example : , Get the random precent index with randsample and swap with strrep
code :
% Input
swapStr = 'AB';   
swapPerc = 0.4; % 40%

% Get index to swap
hasPair = find(~cellfun('isempty', regexp(A_in, swapStr)));
swapIdx = randsample(hasPair, ceil(numel(hasPair) * swapPerc));

% Swap char pair
A_out = A_in;
A_out(swapIdx) = strrep(A_out(swapIdx), swapStr, fliplr(swapStr));
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