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DXpopup position offset top relative to a variable


By : Shawn Meredyk
Date : October 15 2020, 08:10 AM
it helps some times You put offsetY variable inside a string. It wont be recognized. Try creating a string offsetY. So to achieve your functionality:-
code :
[position]= "{ my: 'left top', at: 'left top', offset: offsetY}"
offsetY: string = "0 150";


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JQuery - .position isn't returning offset relative to parent


By : YinJRJ
Date : March 29 2020, 07:55 AM
I wish this help you If I am correct, I think this is a CSS issue, not necessarily a jQuery one.. My understanding is that the default value of the CSS "position" property is static (not absolute, relative), and positioning is calculated relative to the first ancestor that is not set to static.
If the element has no ancestor with non-static position, the element will be positioned relative to the html block.
code :
<html>
  <style type="text/css">
    .divOuter { border:1px solid Green;  width:350px; height:50px; padding:2px; margin-left:80px; }
    .divInner{border:1px solid Blue;  width:200px; height:50px; padding:2px; position:absolute; left:100px;}
 </style>
 <body>
 <div class="divOuter">
  <div  class="divInner">
     positioned relative to html block 
  </div>
  </div>
      <div  class="divOuter" style="position:relative;">
   <div class="divInner">
     positioned relative to parent div
  </div>
  </div>
  </body>
  </html>

wrong offset in relative position


By : maineiac
Date : March 29 2020, 07:55 AM
it fixes the issue try using .offset(), it gives position of element relative to document, change
code :
var offset = $(this).position();
var offset = $(this).offset();
$('.col-md-4').hover(function(){
    var childPosition = $(this).offset();
    var parentPosition = $(this).parent().offset();
    var actualOffset = {
        top: childPosition.top - parentPosition.top,
        left: childPosition.left - parentPosition.left
    }
    var height = $(this).height();
    console.log(offset);
    $('#shadow2').stop(true, true).animate({
        'left': actualOffset.left,
        'top': actualOffset.top + height + 10
    });
....

Why does a relative measurement offset the starting position of an element?


By : user2141606
Date : March 29 2020, 07:55 AM
will help you This is the intended behavior of GSAP's from function of their TimeLine.
What it's doing:
code :
trackMaster.to( 
    $('.particle')[i], 
    randomNumber(10,100), 
    { top:'+=30px', ease: Linear.easeNone, repeat: -1 }, 
    0 
);

How do I get parent div to exactly contain child div that has position: relative with offset?


By : Prasad Kulkarni
Date : March 29 2020, 07:55 AM
this one helps. Instead of using an offset, use a negative margin to move the child instead:
code :
.second{
    margin-top:-20px;
    background-color: rgba(50,50,50,.5);
    height: 100px;
}

Position relative div getting different offset


By : Amar Maarof
Date : March 29 2020, 07:55 AM
hope this fix your issue As mentioned in MDN HTMLElement.offsetTop returns position relative to the parent element . So in your example document.getElementById('div2-child').offsetTop returns top position relative to div2
So, if you want the position relative to window(viewport) you need to add child position with it's parent position like below:
code :
document.getElementById('demo').innerHTML = document.getElementById('div1').offsetTop + " " + document.getElementById('div2').offsetTop + " " + (document.getElementById('div2-child').offsetParent.offsetTop + document.getElementById('div2-child').offsetTop);
document.getElementById('demo').innerHTML = document.getElementById('div1').offsetTop + " " + document.getElementById('div2').offsetTop + " " + (document.getElementById('div2-child').getBoundingClientRect().top);
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