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Add int to date SQL


Add int to date SQL

By : user2176009
Date : October 14 2020, 02:23 PM
I hope this helps . I have a table Scadenziario with many columns. , You can use DATE_ADD() function:
code :
select ID, Scadenza, Frequenza, DATE_ADD( Scadenza, INTERVAL Frequenza DAY) 
FROM scadenziario
WHERE Scadenza < '2018-12-11'


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Date picker scrolls to past date, even though minimum date is set to current date

Date picker scrolls to past date, even though minimum date is set to current date


By : goutham pajjuru
Date : March 29 2020, 07:55 AM
With these it helps I got the same issue as you and fixed it with only setting the date to the maximum date manually (in this case I set the limit to the current date):
code :
- (IBAction)pickerValueChanged:(id)sender {

    dispatch_async(dispatch_get_main_queue(), ^{
        UIDatePicker *datePicker = (UIDatePicker *)sender;

        if ([self.datePicker.date compare:[NSDate date]] == NSOrderedDescending) {

            datePicker.date = [NSDate date];
        }

    });
}
I want datepicker in that END date as current date and START date as 7 days previous to END date in Jquery r Bootstrap

I want datepicker in that END date as current date and START date as 7 days previous to END date in Jquery r Bootstrap


By : Norwigi
Date : March 29 2020, 07:55 AM
I hope this helps you . , HTML
code :
<input type="text" id="start">
<input type="text" id="end">
$(document).ready(function () {
$("#end").datepicker({
    dateFormat: "dd-M-yy",
    minDate: 0,
    onSelect: function () {
        var start = $('#start');
        var startDate = $(this).datepicker('getDate');
        startDate.setDate(startDate.getDate() - 7);
        start.datepicker('option', 'minDate', startDate);
        start.datepicker('option', 'maxDate', $(this).datepicker('getDate'));
    }
});
$('#start').datepicker({
    dateFormat: "dd-M-yy"
});
});
Why when I choose a date (using HTML5 date), Javascript shows different date than the date from the date picker?

Why when I choose a date (using HTML5 date), Javascript shows different date than the date from the date picker?


By : qiu_-
Date : March 29 2020, 07:55 AM
To fix the issue you can do The date picker is picking the date in your local time zone. That is, when a date is selected it's set as midnight of your local time. When displaying the date, it's being displayed in UTC (that is what the "Z" at the end signifies). Your local time zone appears to be 8 hours ahead of UTC (Russia?), so midnight of your time is 16:00 the previous day UTC. In other words, they're both exactly the same time--they're just expressed in differing time zones.
The toString() method of displaying a Date (which you're implicitly calling since you're not specifying how the date should be displayed) shows the Date in UTC with the cryptic format you see there. It was designed to be more machine readable than human readable. To display the date in your local time zone (and in a nicer format), display the date with the toDateString() method instead:
code :
{{example.value.toDateString()}}
Expected `dd-MM-yyyy` to be a date. i am using Date() to change the date data to assure it is a date datatype

Expected `dd-MM-yyyy` to be a date. i am using Date() to change the date data to assure it is a date datatype


By : Zubair
Date : March 29 2020, 07:55 AM
will be helpful for those in need Use momentJS and your life related to dates will be simple, use toDate() of moment to convert moment Object to javascript Date Object
code :
$scope.wagetyperanges[i].fromDate = moment($scope.wagetyperanges[i].fromDate, "DD-MM-YYYY").toDate(); //31-03-2016
How to Select First Date, Previous Date, Latest Date where first date is higher than a reference date

How to Select First Date, Previous Date, Latest Date where first date is higher than a reference date


By : Sabrina
Date : March 29 2020, 07:55 AM
hop of those help? I want to SELECT the Latest Date, the Second Latest Date and the First Date FROM a table1 where the First Date is higher than a reference Date found in another table2. And that reference Date should also be the latest from that table2. I have a solution, supposed to be. But the problem is, the solutions will not return an output if there is ONLY 1 record from table1. Example of the tables: , The following query answers your question:
code :
SELECT
    RegID,
    LatestDateOfCalving,
    MIN(DateOfAI) AS 1stDateOfAI,
    REPLACE(SUBSTRING_INDEX(GROUP_CONCAT(DateOfAI ORDER BY DateOfAI DESC), ',', 2), CONCAT(MAX(DateOfAI), ','), '') AS PreviousAIDate,
    MAX(DateOfAI) AS LatestAIDate
FROM (
    SELECT
        t1.RegID,
        LatestDateOfCalving,
        DateOfAI,
        IF(DateOfAI >= LatestDateOfCalving, 1, 0) AS dates
    FROM table1 AS t1
    INNER JOIN (
        SELECT
            RegID,
            MAX(DateOfCalving) AS LatestDateOfCalving
        FROM table2 GROUP BY RegID
    ) AS tt2 ON t1.RegID = tt2.RegID) AS x
WHERE dates = 1
GROUP BY RegID
HAVING COUNT(dates) >= 3;
+--------+---------------------+-------------+----------------+--------------+
| RegID  | LatestDateOfCalving | 1stDateOfAI | PreviousAIDate | LatestAIDate |
+--------+---------------------+-------------+----------------+--------------+
| 2GP001 | 2017-04-12          | 2017-11-10  | 2017-11-30     | 2017-12-23   |
+--------+---------------------+-------------+----------------+--------------+
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