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Python 3 if/elif issue


By : user2176013
Date : October 14 2020, 02:23 PM
To fix the issue you can do It's because you're missing an in use_stim in the first if statement after the "You bet";
code :
  if "ok" in use_stim or "okay" in use_stim or "yes" in use_stim or "sure" in use_stim or "you bet" in use_stim or "good idea" in use_stim:
        char_health = char_health + char_stim_heal
        char_stims = char_stims - 1
        print(char_name + ": Using stimpak, I feel better")  
        print("")
        print("***STATS***")
        print("Health:" + str(char_health)) 
        print("Stimpaks:" + str(char_stims))
        print("***STATS***")
        print("")            
        search_next = str.lower(input(char_name + ": Alright, what's next? Weapons or amunition?"))
        print(username + ": " + search_next)

    elif "no" in use_stim or "nope" in use_stim or "never" in use_stim or "no way" in use_stim or "not a chance" in use_stim or "i don't think so" in use_stim:
        print(user_name + ": " + use_stim)
        print(char_name + ": Alright, i'll save it for later.")
        char_stims = 1
        char_health = 75
        print("")
        print("***STATS***")
        print("Health:" + str(char_health)) 
        print("Stimpaks:" + str(char_stims))
        print("***STATS***")
        print("")
print(char_name + ": Using stimpak, I feel better\n") <<< Add \n here  
print("")                                             <<< Remove this
print("***STATS***")
print("Health:" + str(char_health)) 
print("Stimpaks:" + str(char_stims))
print("***STATS***\n")                                <<< Add \n here 
print("")                                             <<< Remove this


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Python if/elif issue with random.randint


By : mr_wook
Date : March 29 2020, 07:55 AM
it fixes the issue You're comparing an integer to a list.
To do what you're trying to do, here's one way:
code :
if i in range(0, 20):
    print("You caught nothing!")
elif i in range(20, 40):
    print("You caught a Minnow! +10 points.")
    score += 10

Best practices for Python if-elif-elif-elif when dispatching requests


By : TowerzZz
Date : March 29 2020, 07:55 AM
like below fixes the issue If request_type can be present in more than one category, you could use a tuple to loop through them in priority order:
code :
categories = (
    (category1, dispatch1method), 
    (category2, dispatch2method),
    (category3, dispatch3method),
    (category4, dispatch4method),
    (category5, dispatch5method),
)

next(method for cat, method in categories if request_type in cat)(arguments)
category_dispatch = {}
for cat, dispatch in categories:
    category_dispatch.update(dict.fromkeys(cat.keys(), dispatch))
category_dispatch[request_type](arguments)
category_dispatch = {}
for cat, dispatch in reversed(categories):
    category_dispatch.update(dict.fromkeys(cat.keys(), dispatch))

Python: Issue with Elif Break


By : Neeru Singh
Date : March 29 2020, 07:55 AM
To fix the issue you can do I'm trying to make a simple program that will take all of your lottery numbers, and compare them (using set intersect) with the winning numbers that you input. , Replace
code :
elif len(my_numbers) == 5:
elif len(numbers) == 5:
def set_convert(mylist):
    conversion = set(mylist)
    return conversion

If Elif issue / Selenium Python


By : ec1ecitc
Date : October 14 2020, 02:22 PM
seems to work fine This is selenium behavior will throw exception if no element found, wrap it in try-except
code :
first_product = None
try:
    first_product = driver.find_element_by_css_selector("div[class='search-did-you-mean']"
except: pass

if first_product:
    .....

Elif and Else Issue in Python 3


By : Dalton Scott
Date : March 29 2020, 07:55 AM
I hope this helps you . The else does not take a conditional. If you want to narrow your digit=9 to w, x, y or z, then you need to make that an elif as well.
Otherwise,
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