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Can't delete product combinations on 1.7.4.3


By : user2176270
Date : October 14 2020, 02:21 PM
Any of those help I solve it, by disabling the caches, and I have enabled the force compilation of templates and add this code to your .htaccess
code :
<RequireAny>
Require method DELETE GET POST PUT OPTIONS
</RequireAny>

<Limit GET POST PUT DELETE HEAD OPTIONS>
Order allow,deny
Allow from all
</Limit>
<LimitExcept GET POST PUT DELETE HEAD OPTIONS>
Order deny,allow
Deny from all
</LimitExcept>


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I need to delete the space after product description in woo commerce product page


By : user1701920
Date : March 29 2020, 07:55 AM
this one helps. I guess you wanted to hide that "related products" section below the product description. You should add some CSS
code :
section.related.products {
  display: none;
}

Python Combinations and product


By : Kevin Mulhern
Date : March 29 2020, 07:55 AM
it should still fix some issue Here is a more robust/general way of doing the sort of thing you want. I start by defining a helper function:
code :
from itertools import combinations, chain, product

def subsets_of_length(s, lengths):
    return chain.from_iterable(combinations(s,l) for l in lengths)
>>>> list(subsets_of_length(['a','b','c'], range(2,4)))
[('a', 'b'), ('a', 'c'), ('b', 'c'), ('a', 'b', 'c')]

>>>> list(subsets_of_length(['d','e'], range(0,2)))
[(), ('d',), ('e',)]
>>>> for choices in product(
         subsets_of_length(['a','b','c'], range(2,4)),
         subsets_of_length(['d','e'], range(0,2)),
     ):
         print(' '.join(str(subset) for subset in choices))

('a', 'b') ()
('a', 'b') ('d',)
('a', 'b') ('e',)
('a', 'c') ()
('a', 'c') ('d',)
('a', 'c') ('e',)
('b', 'c') ()
('b', 'c') ('d',)
('b', 'c') ('e',)
('a', 'b', 'c') ()
('a', 'b', 'c') ('d',)
('a', 'b', 'c') ('e',)
>>>> for choices in map(chain.from_iterable,product(
         subsets_of_length(['a','b','c'], range(2,4)),
         subsets_of_length(['d','e'], range(0,2)),
     )):
         print(' '.join(column for column in choices if column))

a b
a b d
a b e
a c
a c d
a c e
b c
b c d
b c e
a b c
a b c d
a b c e
for choices in map(chain.from_iterable,product(
    subsets_of_length(['AA','AS','AD'], [1]),       #only one of these
    subsets_of_length(['BB','BC'], [1,2]),          #at least one of these
    subsets_of_length(['CD','CF','CG'], [0,1,2,3]), #All, 1, 2 or none of these
)):
    print(' '.join(column for column in choices if column))

How can i find unique combinations of 2 columns, delete not unique combinations, keeping only first rows in pandas


By : cha
Date : March 29 2020, 07:55 AM
Does that help I have a dataset that contains 2 columns. And there are data combinations. I want to find if there are not unique combinations and delete them keeping only the first row. , I believe you need sorting each row and remove duplicates:
code :
df = (pd.DataFrame(np.sort(df[['dim', 'linked_dim']], axis=1),
                   columns=['dim', 'linked_dim'])
        .drop_duplicates())
print (df)
                     dim        linked_dim
0   Customer group$Large  DEPARTMENT$Sales
1  Customer group$Medium  DEPARTMENT$Sales
2   Customer group$Small  DEPARTMENT$Sales

Can Cartesian product of two lists return all the combinations except the combinations involving two same elements?


By : user3018564
Date : March 29 2020, 07:55 AM
it fixes the issue For Example , Try it with itertools permutations
code :
import itertools
list(itertools.permutations(['a','b','c'], r=2))
[('a', 'b'), ('a', 'c'), ('b', 'a'), ('b', 'c'), ('c', 'a'), ('c', 'b')]
list(itertools.permutations([[1,2],[2,3],[1,2]], 2))
[([1, 2], [2, 3]), ([1, 2], [1, 2]), ([2, 3], [1, 2]), ([2, 3], [1, 2]), ([1, 2], [1, 2]), ([1, 2], [2, 3])]

Woocommerce when deleting a product, automatically also delete the product gallery and product image


By : stella droid
Date : March 29 2020, 07:55 AM
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