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yield return method optimized away when it shouldn't be

By : gafa
Date : October 14 2020, 02:21 PM
wish help you to fix your issue IEnumerable objects have deferred execution which means they are executed when they are accessed for iterating. When we start iterating or materialize an object of it to a List or Array then it's actually invoked.
If you add ToList() call to your ForEach method, you will see the expected output:
code :
After(ForEach(Sample(10), v => item = v).ToList(), () => Console.WriteLine(item));
static IEnumerable<int> Sample(int count)
    Console.WriteLine("Sample Invoked");
    for (int i = 0; i < count; i++)
        yield return i;

static IEnumerable<int> ForEach(IEnumerable<int> items, Action<int> action)
    Console.WriteLine("ForEach Invoked:");
    foreach (int item in items)
        yield return item;
int item = -1;
After(ForEach(Sample(10), v => item = v), () => Console.WriteLine(item));

After(ForEach(Sample(10), v => item = v).ToList(), () => 

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Yield return and method state

By : shakib
Date : March 29 2020, 07:55 AM
I hope this helps you . My solution to this is to not lazily load from the database. I have a feeling it's not a good idea to load from a database lazily anyway. Instead I have added to the ExecuteReader method a transform function Func parameter. The data records that are read are then immediately converted into objects, rather than expecting the caller to take an IEnumerable and do something with it.
I liked the concision of the yield return version, but I think ultimately it is better not to lazily load from the DB.

Will the call to the last awaited method be optimized to never return INTO the method if there is nothing after it?

By : Yash Gautam
Date : March 29 2020, 07:55 AM
I wish did fix the issue. One of the scenarios where it is needed is when the last method throws an exception. Await will throw in the context of the calling method.
You may set a breakpoint on the closing brace in the method - thus, the last call returns.

Unity c# Cannot return a value from iterators. Use the yield return statement to return a value, or yield break to end t

By : Dennis Cho
Date : March 29 2020, 07:55 AM
will be helpful for those in need My suspicion is that you are simply trying to exit the co-routine when the ActionCancelled is set to true, A slight modification and you end up with this.
You cannot return a value in a co-routine but what you can do is call an external method and BREAK the (stops the forloop in it's tracks)
code :
    IEnumerator PayAdditionalCostAndPlay()
        if (DiscardCost > 0 && ValidSpell())
            Player.ActionCancelled = false;
            Debug.Log("this card has an additional discard cost");
            for (int i = 0; i < DiscardCost; i++)
                Player.NeedTarget = 21; // a card in hand to discard

                while (Player.NeedTarget > 0) yield return new WaitForSeconds(0.1f);
                if (Player.ActionCancelled)
                    Debug.Log("action cancelled");
                    OnPlayerActionCancelled(); // optional, obviously
                    break; // stop processing the for-loop
            if (!Player.ActionCancelled)
                foreach (GameObject target in Player.targets) //discard

    private void OnPlayerActionCancelled()
        // Do something when a player action is cancelled

Async method does not recognize yield return method?

By : user2863228
Date : March 29 2020, 07:55 AM
hop of those help? PROBLEM , yield doesn't yield unless its enumerated. In this case
code :
model.Pages = content.GetPages();
model.Pages = content.GetPages().ToList();

If you want to wrap a method that yields, does the wrapper method need to yield also, or will a return suffice?

By : Markus Wettstein
Date : March 29 2020, 07:55 AM
I hope this helps . In general, you don't need to wrap it with yield, unless you are intending to do some extra work. For instance. if you want to multiply the each value by 2:
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