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Why does my for loop (python) shift behaviour after 4 iterations?

By : Amarendra
Date : October 14 2020, 02:21 PM
wish helps you text.index always returns the first index found. Since you iterate your seq letter by letter, the first time you hit a previously found letter you get weird results.
The 5th letter is the first duplicate, a c, and so text.index('c') is returning the index of the first c, 1, and not 4 as you expect - and you duplicate the previous time you hit c.
code :
for a in range(len(text)-(n-1)):
    b = text[a:a+n]
    c = len(re.findall(b, text, overlapped=True))
    print ("the count for " + b + " is " + str(c))
>>> from collections import Counter
>>> Counter((seq[i:i+3] for i in range(len(seq)-2)))
Counter({'TTT': 4, 'TGC': 2, 'GCA': 2, 'CAT': 2, 'ATT': 2, 'ACT': 1, 'CTG': 1, 'TTG': 1})

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How can I limit iterations of a loop in Python?

By : Flutter
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Say I have a list of items, and I want to iterate over the first few of it: , How can I limit iterations of a loop in Python?
code :
for index, item in enumerate(items):
    if index == limit:
for index, item in zip(range(limit), items):
    print(index, item)
from itertools import izip
for index, item in izip(xrange(limit), items):
for item in itertools.islice(items, 0, stop):
for index, item in enumerate(islice(items, limit)):
    print(index, item)
def enumerate(collection, start=0):  # could add stop=None
    i = start
    it = iter(collection)
    while 1:                         # could modify to `while i != stop:`
        yield (i, next(it))
        i += 1
_enumerate = enumerate

def enumerate(collection, start=0, stop=None):
    if stop is not None:
        return zip(range(start, stop), collection)
    return _enumerate(collection, start)
for linenum, line in enumerate(source,1):  print linenum, line
for item in items[:limit]: # or limit+1, depends
for index, element in zip(range(limit), items):
for index, item in enumerate(islice(items, limit)):
for element in islice(items, 0, limit):

How to use exception handling in a loop (for n iterations) in python so that results are stored in a file but loop doesn

By : Deadlift
Date : March 29 2020, 07:55 AM
This might help you Have a look into the below code logging in the file can be done as per requirement :
code :
for i in range(0,n):
        list =['name','age']
        for word in list:
            if word in str:
                print('output verified')
                # instead of a generic exception a specific exception can be raised
                raise Exception('unmatched values')
                print('unmatched values for iteration n')
    except Exception:
        TestCase.status = FAIL
        print "Log you result in a file "
        # raise ex  - need not be here

Python - For Loop ( two parallel iterations)

By : user2160432
Date : March 29 2020, 07:55 AM
Any of those help I am working on the estimation module of a prototype. The purpose is to send proper seasonality variation parameters to the forecaster module.
code :
orders = np.array([2, 6, 10, 24])
z = np.array([0.08, 0.11, 0.25, 0.01, 0.66, 0.19, 0.45, 0.07])
doy = np.arange(365) + 1

s = 0
for k in range(len(orders)):
    s += z[2 * k    ] * np.sin(orders[k] * np.pi * doy / 365.)
    s += z[2 * k + 1] * np.cos(orders[k] * np.pi * doy / 365.) 
s = np.exp(s)

If-else condition in loop: future iterations overwrite results of previous iterations

By : shree tambe
Date : March 29 2020, 07:55 AM
wish helps you De-highlight everything first, then highlight the current selection.
If selectedItem already is a pointer to the only element you want to highlight, you don't need to search for it, you only need:
code :
Q_FOREACH (Item *item, items)

For Loop for n iterations-Python

By : Ranj Kumari
Date : March 29 2020, 07:55 AM
it fixes the issue I have a simple For Loop in a python script:
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